HDU 1213(How Many Tables)

Use disjoint-set , apply the basic template.

#include <iostream>
using namespace std;
const int MAXN = 1005;

int father[MAXN]; //父结点

//初始化并查集
void makeSet(int n)
{
	for (int i = 1; i <= n; i++)
		father[i] = i;
}

//查找x所在集合的代表元素(所在树的根结点)
int find(int x)
{
	if (x != father[x])
		father[x] = find(father[x]);
	return father[x];
}

//合并x所在集合和y所在集合
void unionSet(int x, int y)
{
	int fx = find(x);
	int fy = find(y);
	if (fx != fy)
		father[fx] = fy;
}

int main()
{
	int T;
	cin >> T;
	while (T--)
	{
		int N, M;
		cin >> N >> M;
		makeSet(N);
		int A, B;
		for (int i = 0; i < M; i++)
		{
			cin >> A >> B;
			unionSet(A, B);
		}
		int ans = 0; //桌子数量
		for (int i = 1; i <= N; i++)
		{
			if (i == father[i])
				++ans;
		}
		cout << ans << endl;
	}
	return 0;
}

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Origin blog.csdn.net/Intelligence1028/article/details/104637652