Python fifth day job title

  1. Please list each element by "_" link up.

    users = ['李少奇','李启航','渣渣辉']
  2. Please list each element by "_" link up.

    users = ['李少奇','李启航',666,'渣渣辉']
  3. Please tuples v1 = all elements (11,22,33) is added to the list of v2 = [44,55,66] in.

  4. Please tuples v1 = all elements of the even-indexed location (11,22,33,44,55,66,77,88,99) is added to the list of v2 = [44,55,66] in.

  5. The dictionary keys and values ​​added to the key_list and value_list two lists, such as:

    key_list = []
    value_list = []
    info = {'k1':'v1','k2':'v2','k3':'v3'}
  6. 字典dic = {'k1': "v1", "k2": "v2", "k3": [11,22,33]}

    a. 请循环输出所有的key
    b. 请循环输出所有的value
    c. 请循环输出所有的key和value
    d. 请在字典中添加一个键值对,"k4": "v4",输出添加后的字典
    e. 请在修改字典中 "k1" 对应的值为 "alex",输出修改后的字典
    f. 请在k3对应的值中追加一个元素 44,输出修改后的字典
    g. 请在k3对应的值的第 1 个位置插入个元素 18,输出修改后的字典
  7. Please print each cycle k2 corresponding element values.

    info = {
        'k1':'v1',
        'k2':[('alex'),('wupeiqi'),('oldboy')],
    }
  8. A character string "k: 1 | k1: 2 | k2: 3 | k3: 4" processed into a dictionary { 'k': 1, 'k1': 2 ....}

  9. write the code

    """
    有如下值 li= [11,22,33,44,55,66,77,88,99,90] ,将所有大于 66 的值保存至字典的第一个key对应的列表中,将小于 66 的值保存至第二个key对应的列表中。
    
    result = {'k1':[],'k2':[]}
    """
  10. Output of goods list, the user enters the serial number, the user selects the display of goods

    """
    商品列表:
      goods = [
            {"name": "电脑", "price": 1999},
            {"name": "鼠标", "price": 10},
            {"name": "游艇", "price": 20},
            {"name": "美女", "price": 998}
        ]
    要求:
    1:页面显示 序号 + 商品名称 + 商品价格,如:
          1 电脑 1999 
          2 鼠标 10
          ...
    2:用户输入选择的商品序号,然后打印商品名称及商品价格
    3:如果用户输入的商品序号有误,则提示输入有误,并重新输入。
    4:用户输入Q或者q,退出程序。
    """
  11. Look at the code written results

    v = {}
    for index in range(10):
        v['users'] = index
    print(v)

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Origin www.cnblogs.com/yuancw/p/11456383.html