The fifth day of learning python --- basics (3)

1. Square Matrix II

It didn’t feel like it was written in this way before, but I think this idea is pretty good

m=[[0 for i in range(105)]for j in range(105)]
while True:
    n=int(input())
    if n==0:
        exit()
    for i in range(0,n):
        m[i][i]=1
    for i in range(n):
        for j in range(i+1,n):#因为会把另外一边操作了，所以不用管另一边
            m[i][j]=m[i][j-1]+1
            m[j][i]=m[j-1][i]+1

    for i in range(0,n):
        for j in range(0,n):
            print(m[i][j],end=' ')
        print()
    print()

2. The right area of ​​the array

Writing method one:

I feel that python is really flexible

method = input()

res = 0 
count = 0
input()
for i in range(1,11):
    data = list(map(lambda x:float(x),input().split(" ")))
    if i<6:
        res += sum(data[12-i:])
        count += len(data[12-i:])
    else:
        res += sum(data[i+1:])
        count += len(data[i+1:])

if method == "S":
    print("{:.1f}".format(res))
else:
    print("{:.1f}".format(res/count))

Writing method two:

It's really simple! ! learn! get it!

t, i = input(), [[float(y) for y in input().split()] for x in range(12)]
ans=sum([sum([i[x][y] for y in range(12-x if x<=5 else 12-(5-(x-6)),12)]) for x in range(1,11)])
print("%.1f"%(ans if t=="S" else ans/30))

3. Square matrix I

Thinking questions, hmm! Think of it and make it!

n = int(input())

while n != 0:
    for i in range(1, n + 1):
        for j in range(1, n + 1):
            print(min(i, n - i + 1, j, n -j + 1), end=" ")
        print()
    print()
    n = int(input())

Fourth, the number of numbers in the string

i.isdigit() is a string method in Python, used to determine whether all characters in a string are digits. If so, return True; otherwise, return False.

s = input()
c = 0
for i in s:
    if i.isdigit():
        c+=1
print(c)

5. Circular restraint

I was stunned by the flexibility of python again! !

n = int(input())
p1 = [["Hunter","Gun"],["Gun","Bear"],["Bear","Hunter"]]
for i in range(n):
    n = input().split(" ")
    if n[0] == n[-1]:
        print("Tie")
    elif n in p1:
        print("Player1")
    else:
        print("Player2")

6. String plus spaces

Writing method one:

s=input()
for i in s:
    print(i,end=' ')

Writing method two:

print(" ".join(input()))

Writing method three:

for c in input():
    print(c, end = ' ')

Seven, replace the string

Writing method one:

print(input().replace(input(),'#'))

Writing method two:

s, t = input(), input()
for c in s:
    if c == t:
        print('#', end = '')
    else:
        print(c, end = '')

Eight, string insertion

Writing method one:

try except because he did not specify the number of inputs

while True:
    try:
        str,substr=input().split()
        _max=max(str)
        i=str.index(_max)
        s=str[:i+1]+substr+str[i+1:]
        print(s)
    except EOFError:
        break

Writing method two:

sys.stdin.readlines() reads multiple lines of input into

import sys
lines=sys.stdin.readlines()
for i in range(len(lines)):
    str_, substr_ = lines[i].strip().split()[0], lines[i].strip().split()[1]
    max_ = max(str_)
    index = str_.index(max_)
    print(str_[:index+1] + substr_ + str_[index+1:])

Writing method three:

enumerate

Use the enumerate() function to traverse the string, and each cycle will return the current character and its corresponding subscript.

ord()

Use the ord() function to convert it to an ASCII code value and compare it with the current maximum value

while True:
    try:#跟我自己的写法是一样的
        str,substr = input().split(" ")
        max = 0
        index = 0
        for i,s in enumerate(str):
            if (ord(s) > max):
                max = ord(s)
                index = i
        str_list = list(str)
        str_list.insert(index + 1 ,substr)
        str = "".join(str_list)
        print(str)
    except:
        break