python eighth day job

A: for loop

Nested loop of 1.1 for 99 print multiplication table

count = 0
for i in range(1, 10):
    for a in range(1, i + 1):
        count = i * a
        print('{x} * {z} = {c}    '.format(z=i, x=a, c=count), end='\t')
    print()

Nesting of 1.2 for loop print pyramid

Tip follows

'''

#max_level=5

         *          #current_level=1，空格数=4，*号数=1
        ***       #current_level=2,空格数=3,*号数=3
       *****      #current_level=3,空格数=2,*号数=5
      *******     #current_level=4,空格数=1,*号数=7
     *********    #current_level=5,空格数=0,*号数=9

#数学表达式

空格数=max_level-current_level
*号数=2*current_level-1
'''

# 方案一
y = '*'
for i in range(5):
    x = (i * 2 + 1) * y
    print(x.center(10, ' '))
# 方案二
y = '*'
for i in range(5):
     print('{0: ^10}'.format((i * 2 + 1) * y))

For + 1.3 with rewrite the code range today morning dictation as tomorrow dictation content

username = 'egon'
password = '123'
for i in range(3):
    user_name = input('your name:>')
    user_pwd = input('your password:>')
    if user_name == username and user_pwd == password:
        print('登陆成功')
        while True:
            cmd = input('请输入您的命令>:')
            if cmd == 'q':
                break
            else:
                print('命令{x}正在运行'.format(x=cmd))
        break
    else:
        print('账号密码错误请重试')
else:
    print('三次登陆失败，自动退出')

II: String operations

Write the code, the following variables, functions as required to implement each (a total of 6 points, 0.5 points each Meixiao Ti)

name = " aleX"

1) corresponding to the variable name is removed on both sides of the space values, and outputs the processing result

res1 = name.strip()
print(res1)

2) determination whether the value corresponding to the variable name beginning with "al", and outputs the result


res2 = name.startswith('al')
print(res2)

3) corresponding to the variable name is determined whether the value of an "X" at the end, and outputs the result


res3 = name.endswith('X')
print(res3)

4) the value corresponding to the variable name in the "l" is replaced with "p", and outputs the result

res4 = name.replace('l','p')
print(res4)

5) The name of the corresponding variable value in accordance with "l" division, and outputs the result.

res5 = name.split('l')
print(res5)

6) The name becomes a variable value corresponding to upper case, and outputs the result


res6 = name.upper()
print(res6)

7) The name corresponding to the variable value becomes lower case, and the output


res7 = name.lower()
print(res7)

8) Please outputs of the two character values ​​corresponding to the variable name?

res8 = name[1]
print(res8)

9) Please output the first three characters of the name value of the corresponding variable?

res9 = name[0:3]
print(res9)

10) Please post the output value of two variables corresponding character name?


res10 = name[-2:]
print(res10)

11) Request output value corresponding to the variable name index where "e" position?


res11 = name.find('e')
print(res11)

12) acquisition sequences, removing the last character. Such as: oldboy then get oldbo.

res12 = name [:-1]
print(res12)