Learn Python the fifth day of the exercises 2019.07.18
1) corresponding to the variable name is removed on both sides of the space values, and outputs the processing result
code:
name = " aleX"
if name[0]==' ':
name=name[1:]
if name[-1]==' ':
name=name[:-1]
print(name)
operation result:
aleX
2) determination whether the value corresponding to the variable name beginning with "al", and outputs the result
code:
name = " aleX"
if name[:2]=='al':
print('name变量是以al开头的')
else:
print('name变量不是以al开头的')
operation result:
variable name does not begin with the al
3) corresponding to the variable name is determined whether the value of an "X" at the end, and outputs the result
code:
name = " aleX"
if name[-1]=='X':
print("name变量是以X为结尾的")
else:
print("name变量不是以X为结尾的")
operation result:
X is a variable name ending with
4) the value corresponding to the variable name in the "l" is replaced with "p", and outputs the result
code:
name = " aleX"
num = len(name)
for i in range(num):
if name[i]=='l':
name = name.replace('l','p')
print(name)
operation result:
apeX
5) The name of the corresponding variable value in accordance with "l" division, and outputs the result
code:
name = " aleX"
new_name = name.split('l')
print(new_name)
operation result:
[' a', 'eX']
6) The name becomes a variable value corresponding to upper case, and outputs the result
code:
name = " aleX"
new_name = name.upper()
print(new_name)
operation result:
ALEX
7) The name corresponding to the variable value becomes lower case, and the output
code:
name = " aleX"
new_name = name.lower()
print(new_name)
operation result:
alex
8) Make the second character output value corresponding to the variable name
code:
name = " aleX"
print(name[1])
operation result:
a
9) Make the first three characters output value corresponding to the variable name
code:
name = " aleX"
print(name[:3])
operation result:
al
10) outputs the requested value corresponding to the variable name character 2
code:
name = " aleX"
print(name[-2:])
operation result:
eX
11) Request output value corresponding to the variable name index where "e" position
code:
name = " aleX"
num = len(name)
for i in range(num):
if name[i] == 'e':
print(i)
operation result:
3
12) acquisition sequences, removing the last character. Such as: oldboy then get oldbo
code:
name = " aleX"
new_name = name[:-1]
print(new_name)
operation result:
but
1. The following data is stored as a dictionary type
# # 数据:info = "name:Owen|age:18|gender:男"
# # 结果:{'name': 'Owen', 'age': 18, 'gender': '男'}
code:
info = "name:Owen|age:18|gender:男"
new_info = info.split('|')
dict_info = {}
list_info=[]
num = len(new_info)
for i in range(num):
list_info += new_info[i].split(':')
list_num = len(list_info)
for i in range(0,list_num,2):
dict_info.setdefault(list_info[i],list_info[i+1])
print(dict_info)
operation result:
{'name': 'Owen', 'age': '18', 'gender': '男'}
2. Complete data deduplication
# # 数据:t3 = [1, 2, 1, 2, 3, 5, 9]
# # 结果:t3 = [1, 2, 3, 5, 9]
code:
t3 = [1, 2, 1, 2, 3, 5, 9]
# 先将序列转为集合去除重复值,再将集合转回序列输出
new_t3 = list(set(t3))
print(new_t3)
operation result:
[1, 2, 3, 5, 9]
3 have the following values of the set [11,22,33,44,55,66,77,88,99,90 ...]
# # 将所有大于 66 的值保存至字典的第一个key中
# # 将小于 66 的值保存至第二个key的值中
# # 即: {'k1': 大于66的所有值, 'k2': 小于66的所有值}
code:
list_str = [11,22,33,44,55,66,77,88,99,90]
k1_list,k2_list = [],[]
for i in list_str:
if i>66:
k1_list.append(i)
else:
k2_list.append(i)
dict_str = {'k1':k1_list,'k2':k2_list}
print(dict_str)
operation result:
{'k1': [77, 88, 99, 90], 'k2': [11, 22, 33, 44, 55, 66]}
4. Complete phonebook entry (OPTIONAL)
# # 需求:
# '''
# -- 从键盘中录入姓名(不区分大小写):
# -- 姓名必须是全英文字母组成,不是则重新录入姓名,如果是q,代表退出
# -- 从键盘中再录入电话:
# -- 电话必须为字符串中是数字(如'12312312312')且长度必须是11位
# -- 如果出现姓名相同,则保留最后一次电话号码
# -- 形成的数据是有电话分组的,如:第一次录入Owen,13355667788,则会形成
# -- {
# 'O': {
# 'Owen': '13355667788'
# }
# }
# 最终数据,分组名一定大写:
# {
# 'E': {
# 'egon': '17788990000',
# 'engo': '16633445566'
# },
# 'O': {
# 'Owen': '13355667788'
# }
# }
# '''
code:
# 定义一个字典电话本,用来接收存储的信息
dict_nums = {}
# 定义一个信息字典,用来存储姓名和手机号码
dict_info = {}
# 定义一个用来接收新的信息的字典
# 定义个序列用来判断输入的name是否有数字
list_num = ['0','1','2','3','4','5','6','7','8','9']
# 定义一个用来判断的变量
check_name_boolen = True
# 用来判断是不是要退出整个程序
check_quit = True
check_num_boolen = True
# 定义一个判断输入姓名的函数
def check_name(name):
global check_name_boolen
for i in name:
if i in list_num:
print("你输入的name中包含了数字,请重新输入!")
check_name_boolen = False
break
else:
check_name_boolen = True
return check_name_boolen
# 定义一个判断输入姓名的函数
def check_num(num):
global check_num_boolen
num_len = len(num)
for i in num:
if i not in list_num or num_len !=11:
print("你输入的电话号码有误,需要重新输入!")
check_num_boolen = False
break
else:
check_num_boolen = True
return check_num_boolen
#### 程序主题
while check_quit:
name = input("请输入姓名(要求为大小写英文,输入数字需重新输入,按q退出):")
# 对name值进行判断
if name=='q':
print("你选择了退出程序!")
check_quit = False
break
check_name(name)
while check_name_boolen != True:
name = input("请输入姓名(要求为大小写英文,输入数字需重新输入,按q退出):")
check_name(name)
if name == 'q':
print("你选择了退出程序!")
check_quit = False
break
num = input("请输入手机号码(要求长度为11位且必须都为数字,输入错误需重新输入):")
# 对输入的电话号码进行判断
check_num(num)
while check_num_boolen != True:
num = input("请输入手机号码(要求长度为11位且必须都为数字,输入错误需重新输入):")
check_num(num)
# 到了这的时候就已经能够拿到了 有效的输入数据 name 和num.接下来要做的就是将这些数据放到字典中就行了
new_dict = {name,num}
old_dict = dict_nums.values()
if dict_info == {}:
dict_info.setdefault(name,num)
else:
for i in dict_info.keys():
if i == name:
dict_info[name] = num
dict_info.setdefault(name, num)
# check_quit = False
#for i in dict_nums.keys():
if dict_nums == {}:
dict_nums.setdefault(name[0].upper(), dict_info)
else:
for i in dict_nums.keys():
if i == name[0].upper():
dict_nums[i] = new_dict
dict_nums.setdefault(name[0].upper(), new_dict)
print(dict_nums)
operation result:
Please enter your name (required to write the English, enter the number to be re-entered, press q to quit): forever
Please enter your mobile number (required length of 11 and must have a digital input errors need to re-enter): 13721111111
Please enter your name ( required to write the English, enter the number to be re-entered, press q to quit): Owen
Please enter your mobile number (required length of 11 and must have a digital input errors need to re-enter): 12233445566
Please enter your name (capitalization requirements English, enter the number to be re-entered, press q to quit): q
you have chosen to exit the program!
{ 'F': { 'forever ': '13721111111', 'Owen': '12233445566'}, 'O': { 'Owen', '12233445566'}}
The last question there are problems, also need to modify