Java基础--day06

格式化控制台输出

可以使用 System.out.printf方法在控制台上显示格式化输出

public class test {
    public static void main(String[] args) {
        double amount = 12618.98;
        double interestRate = 0.0013;
        double interest = amount * interestRate;
        System.out.printf("Interest is $%4.2f", interest);
    }
}

显示:Interest is $16.40

注意:%不能漏掉,4是域宽度,2是精度,f是格式标识符

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System.out.printf(format, item1, item2, ......, itmek);

常用的格式标识符

标识符 输出 举例
%b 布尔值 true或者false
%c 字符 ‘a'
%d 十进制整数 200
%f 浮点数 46.460000
%e 标准科学记数法形式的数 4.556000e+01
%s 字符串 “Java is fun"

默认情况下,浮点值显示小数点后6位

System.out.printf("%8d%8s%8.1f\n", 1234,"Java", 5.63); 
System.out.printf("%-8d%-8s%-8.1f \n", 1234, "Java", 5.63);

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FormatDemo.java

public class test {
    public static void main(String[] args) {
        System.out.printf("%-10s%-10s%-10s%-10s%-10s\n", "Degree", "Radians", "Sine",
        "Cosine", "Tangent");
        int degrees = 30;
        double randians = Math.toRadians(degrees);
        System.out.printf("%-10d%-10.4f%-10.4f%-10.4f%-10.4f", degrees, randians, Math.sin(randians),
                Math.cos(randians), Math.tan(randians));
    }
}

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第四章编程练习题

4.2 几何:最大圆距离

import java.util.Scanner;
public class CircleDistansce {
    public static void main(String[] args) {
        System.out.print("Enter point 1 (latitude and longitude) in degrees:");
        Scanner input = new Scanner(System.in);
        double x1 = input.nextDouble();
        double y1 = input.nextDouble();
        System.out.print("Enter point 2 (latitude and longitude) in degrees:");
        double x2 = input.nextDouble();
        double y2 = input.nextDouble();

        double earthRadius = 6371.01;           // 记得转换为弧度制 Math.toRadians()
        double d = earthRadius * Math.acos(Math.sin(Math.toRadians(x1)) * Math.sin(Math.toRadians(x2)) +
                Math.cos(Math.toRadians(x1)) * Math.cos(Math.toRadians(x2)) * Math.cos(Math.toRadians(y2 - y1)));

        System.out.print("The distance between the 2 points is:" + d);
    }
}

Enter point 1 (latitude and longitude) in degrees: 39.55 -116.25
Enter point 2 (latitude and longitude) in degrees: 41.5 87.37
The distance between the 2 points is: 10691.79183231593

4.2 圆上面的随机点

import java.util.Scanner;
public class test {
    public static void main(String[] args) {
        final double r = 40;
        double alpha1 = Math.random() * 400;
        double x1 = r * Math.cos(Math.toRadians(alpha1));
        double y1 = r * Math.sin(Math.toRadians(alpha1));
        double alpha2 = Math.random() * 400;
        double x2 = r * Math.cos(Math.toRadians(alpha2));
        double y2 = r * Math.sin(Math.toRadians(alpha2));
        double alpha3 = Math.random() * 400;
        double x3 = r * Math.cos(Math.toRadians(alpha3));
        double y3 = r * Math.sin(Math.toRadians(alpha3));

        double line1 = Math.sqrt(Math.pow(x1 - x2, 2) + Math.pow(y1 - y2, 2));
        double line2 = Math.sqrt(Math.pow(x1 - x3, 2) + Math.pow(y1 - y3, 2));
        double line3 = Math.sqrt(Math.pow(x2 - x3, 2) + Math.pow(y2 - y3, 2));

        double angleA = Math.toDegrees(Math.acos((line1 * line1 - line2 * line2 - line3 * line3) / (-2 * line2 * line3)));
        double angleB = Math.toDegrees(Math.acos((line2 * line2 - line1 * line1 - line3 * line3) / (-2 * line3 * line1)));
        double angleC = Math.toDegrees(Math.acos((line3 * line3 - line2 * line2 - line1 * line1) / (-2 * line2 * line1)));

        System.out.printf("3个角度分别为:%10.2f%10.2f%10.2f", Math.round(angleA * 100) / 100.0,
                Math.round(angleB * 100) / 100.0, Math.round(angleC * 100) / 100.0);
    }
}

3个角度分别为: 129.50 15.14 35.36

Write by Gqq

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转载自www.cnblogs.com/zgqcn/p/12529770.html