Java8新特性——————SimpleDateFormat格式化的线程安全问题

传统时间格式化的线程安全问题

在使用SimpleDateFormat时间格式处理类会出现线程安全问题，而java8新特性中的 DateTimeFormatter时间格式处理类解决了此问题，代码如下：

    @Test
    public static void main(String[] args)throws Exception {
        //出现线程安全问题：异常信息为java.lang.NumberFormatException: For input string: ".22E1.22E1"
/*        SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
        Callable<Date> callable = new Callable<Date>() {
            @Override
            public Date call() throws Exception {
                return sdf.parse("20200220");
            }
        };*/
        //加锁后操作
/*        Callable<Date> callable = new Callable<Date>() {
            @Override
            public Date call() throws Exception {
                return DateFormatThreadLocal.convert("20200220");
            }
        };*/
        //java8时间处理类
        DateTimeFormatter dtf = DateTimeFormatter.ofPattern("yyyyMMdd");
        Callable<LocalDate> callable = new Callable<LocalDate>() {
            @Override
            public LocalDate call() throws Exception {
                return LocalDate.parse("20200220",dtf);
            }
        };
        ExecutorService pool = Executors.newFixedThreadPool(10);
        List<Future<LocalDate>> futures = new ArrayList<>();
        for (int i = 0; i < 10; i++) {
            futures.add(pool.submit(callable));
        }
        for (Future<LocalDate> future : futures) {
            System.out.println(future.get());
        }
        pool.shutdown();
    }

//加锁
class  DateFormatThreadLocal{
    private  static final ThreadLocal<DateFormat> df = new ThreadLocal<DateFormat>(){
        @Override
        protected DateFormat initialValue() {
            return new SimpleDateFormat("yyyyMMdd");
        }
    };

    public static  Date convert(String source) throws ParseException {
        return df.get().parse(source);
    }

计算两个"时间"之间的间隔

@Test
public static void main(String[] args)throws Exception {
    Instant ins1 = Instant.now();
    Thread.sleep(10000);
    Instant ins2 = Instant.now();
    Duration durantion = Duration.between(ins1, ins2);
    System.out.println(durantion.toMillis());//10000毫秒
}