作业练习2

# 作业(必做题):
# 1. 使用while循环输出1 2 3 4 5 6     8 9 10
num = 1
while num <= 10:
    if num == 7:
        num += 1
        continue
    else:
        print(num)
        num += 1

# 2. 求1-100的所有数的和
num = 1
num_sum = 0
while num <= 100:
    num_sum += num
    num += 1
print(num_sum)

# 3. 输出 1-100 内的所有奇数
num = 1
odd_sum = 0
while num <= 100:
    odd_sum += num
    num += 2
print(odd_sum)

# 4. 输出 1-100 内的所有偶数
num = 2
even_sum = 0
while num <= 100:
    even_sum += num
    num += 2
print(even_sum)

# 5. 求1-2+3-4+5 ... 99的所有数的和
num = 1
num_sum = 0
while num <= 99:
    if num % 2:
        num_sum += num
    else:
        num_sum -= num
    num += 1
print(num_sum)

# 6. 用户登陆(三次机会重试)
name = 'tom'
pwd = '111'
num = 1
while num <= 3:
    i_name = input('输入用户名:')
    i_pwd = input('输入密码:')
    if i_name == name and i_pwd == pwd:
        print('登录成功')
        break
    else:
        print('用户名或密码错误(当前第{}次)'.format(num))
        num += 1
else:
    print('已错误3次,请稍后再试')

# #7:猜年龄游戏
#     要求:
#     允许用户最多尝试3次,3次都没猜对的话,就直接退出,如果猜对了,打印恭喜信息并退出
age = 50
l_limit = 1
h_limit = 99
num = 2
while num >= 0:
    gus_age = input('猜一猜oldboy的年龄({}~{}):'.format(l_limit,h_limit))
    gus_age = int(gus_age)
    if gus_age == age:
        print('恭喜,猜对了!')
        break
    elif gus_age < age:
        print('很遗憾,猜小了,还可以猜{}次'.format(num))
        l_limit = gus_age
    else:
        print('很遗憾,猜大了,还可以猜{}次'.format(num))
        h_limit = gus_age
    num -= 1
else:
    print('次数用完,下次再加油吧')

# 8:猜年龄游戏升级版(选做题)
# 要求:
#     允许用户最多尝试3次
#     每尝试3次后,如果还没猜对,就问用户是否还想继续玩,如果回答Y或y, 就继续让其猜3次,以此往复,如果回答N或n,就退出程序
#     如何猜对了,就直接退出
age = 50
l_limit = 1
h_limit = 99
num = 2
while num >= 0:
    gus_age = input('猜一猜oldboy的年龄({}~{}):'.format(l_limit,h_limit))
    gus_age = int(gus_age)
    if gus_age == age:
        print('恭喜,猜对了!')
        break
    elif gus_age < age:
        print('很遗憾,猜小了,还可以猜{}次'.format(num))
        l_limit = gus_age
    else:
        print('很遗憾,猜大了,还可以猜{}次'.format(num))
        h_limit = gus_age
    num -= 1
    while num == -1:
        choice = input('已猜错3次,是否继续,继续输入"Y",退出输入"Q":')
        if choice in ['Y','y']:
            num = 2
        elif choice in ['Q','q']:
            break
        else:
            print('输入不合法,请重新输入')

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转载自www.cnblogs.com/caoyu080202201/p/12449528.html