Codeforces Round #593 (Div. 2) B. Alice and the List of Presents

B. Alice and the List of Presents

time limit per test1 second

memory limit per test256 megabytes

inputstandard input

outputstandard output

Alice got many presents these days. So she decided to pack them into boxes and send them to her friends.

There are n kinds of presents. Presents of one kind are identical (i.e. there is no way to distinguish two gifts of the same kind). Presents of different kinds are different (i.e. that is, two gifts of different kinds are distinguishable). The number of presents of each kind, that Alice has is very big, so we can consider Alice has an infinite number of gifts of each kind.

Also, there are m boxes. All of them are for different people, so they are pairwise distinct (consider that the names of m friends are written on the boxes). For example, putting the first kind of present into the first box but not into the second box, is different from putting the first kind of present into the second box but not into the first box.

Alice wants to pack presents with the following rules:

She won’t pack more than one present of each kind into the same box, so each box should contain presents of different kinds (i.e. each box contains a subset of n kinds, empty boxes are allowed);
For each kind at least one present should be packed into some box.
Now Alice wants to know how many different ways to pack the presents exists. Please, help her and calculate this number. Since the answer can be huge, output it by modulo 109+7.

See examples and their notes for clarification.

Input

The first line contains two integers n and m, separated by spaces (1≤n,m≤109) — the number of kinds of presents and the number of boxes that Alice has.

Output

Print one integer — the number of ways to pack the presents with Alice’s rules, calculated by modulo 109+7

Examples

input

1 3

output

7

input

2 2

output

9

Note

In the first example, there are seven ways to pack presents:

{1}{}{}
{}{1}{}
{}{}{1}
{1}{1}{}
{}{1}{1}
{1}{}{1}
{1}{1}{1}
In the second example there are nine ways to pack presents:

{}{1,2}
{1}{2}
{1}{1,2}
{2}{1}
{2}{1,2}
{1,2}{}
{1,2}{1}
{1,2}{2}
{1,2}{1,2}
For example, the way {2}{2} is wrong, because presents of the first kind should be used in the least one box.

#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <string>
#include <cmath>
#include <stack>
#include <queue>
#include <vector>
#include <set>
#include <map>
#include <functional>
#include <ctime>
#include <iomanip>
#include <sstream>
#include <algorithm>
#define ll long long
#define mes(x,y) memset(x,y,sizeof(x))
#define FAST_IO ios::sync_with_stdio(false);cin.tie(0);cout.tie(0)
using namespace std;
ll GCD(ll a, ll b) {//最大公约数
	return b == 0 ? a : GCD(b, a % b);
}

const ll maxn = 1e9 + 7;
ll _power(ll a, ll b, ll p) { //计算(a^b)%p;
	ll ans = 1;
	while (b) {
		if (b & 1) //等价于b%2,判断b的奇偶性
			ans = ans * a % p; //如果为奇数,证明该位为1,需要乘上a
		a = a * a % p; //计算a^(2^i)
		b >>= 1; //等价于b/=2;
	}
	return ans;
}
int main() {
	ll n, i, j, m;
	while (cin >> n >> m) {
		ll total = _power(2, m, maxn);
		total--;
		total = _power(total, n, maxn);
		cout << total << endl;
	}
}


发布了148 篇原创文章 · 获赞 7 · 访问量 2万+

猜你喜欢

转载自blog.csdn.net/weixin_44417851/article/details/102617050