题目要求：
多线程之间按顺序调用，实现A->B->C
三个线程启动，要求如下：
<p>
AA打印5次，BB打印10次，CC打印15次
接着
AA打印5次，BB打印10次，CC打印15次
......来10轮实现三个方法的。
package com.thekingqj;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;
/**
* 三个线程之间的顺序调用。A->B->C
*/
class ShareResource1 {
private int flag = 1;
private Lock lock = new ReentrantLock();
private Condition c1 = lock.newCondition();
private Condition c2 = lock.newCondition();
private Condition c3 = lock.newCondition();
public void print5() throws InterruptedException {
lock.lock();
try {
while(flag!=1){
c1.await();
}
for (int i = 0; i < 5; i++) {
System.out.println(Thread.currentThread().getName()+"\t"+i);
}
flag=2;
c2.signal();
} finally {
lock.unlock();
}
}
public void print10() throws InterruptedException {
lock.lock();
try {
while(flag!=2){
c2.await();
}
for (int i = 0; i < 10; i++) {
System.out.println(Thread.currentThread().getName()+"\t"+i);
}
flag=3;
c3.signal();
} finally {
lock.unlock();
}
}
public void print15() throws InterruptedException {
lock.lock();
try {
while(flag!=3){
c3.await();
}
for (int i = 0; i < 15; i++) {
System.out.println(Thread.currentThread().getName()+"\t"+i);
}
flag=1;
c1.signal();
} finally {
lock.unlock();
}
}
}
/**
* @Description: 多线程之间按顺序调用，实现A->B->C
* 三个线程启动，要求如下：
* <p>
* AA打印5次，BB打印10次，CC打印15次
* 接着
* AA打印5次，BB打印10次，CC打印15次
* ......来10轮
*/
public class ThreadOrderAccess1 {
public static void main(String[] args) {
ShareResource1 resource = new ShareResource1();
new Thread(() -> {
for (int i = 1; i <= 10; i++) {
try {
resource.print5();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}, "A").start();
new Thread(() -> {
for (int i = 1; i <= 10; i++) {
try {
resource.print10();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}, "B").start();
new Thread(() -> {
for (int i = 1; i <= 10; i++) {
try {
resource.print15();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}, "C").start();
}
}
整合到一个方法：
package com.thekingqj;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;
class ShareResource {
private int flag = 1;
private Lock lock = new ReentrantLock();
private Condition c1 = lock.newCondition();
private Condition c2 = lock.newCondition();
private Condition c3 = lock.newCondition();
public void print() throws InterruptedException {
int m;
lock.lock();
if (Thread.currentThread().getName().equals("A")) {
m = 5;
} else if (Thread.currentThread().getName().equals("B")) {
m = 10;
} else {
m = 15;
}
if (flag == 1 && Thread.currentThread().getName().equals("B")) {
c2.await();
}
if (flag == 1 && Thread.currentThread().getName().equals("C")) {
c3.await();
}
if (flag == 2 && Thread.currentThread().getName().equals("A")) {
c1.await();
}
if (flag == 2 && Thread.currentThread().getName().equals("C")) {
c3.await();
}
if (flag == 3 && Thread.currentThread().getName().equals("A")) {
c1.await();
}
if (flag == 3 && Thread.currentThread().getName().equals("B")) {
c2.await();
}
try {
System.out.println(Thread.currentThread().getName() + "\t\t\t" + m);
for (int i = 0; i < m; i++) {
System.out.println(Thread.currentThread().getName() + "\t" + i);
}
if (Thread.currentThread().getName().equals("A")) {
flag = 2;
c2.signal();
}
if (Thread.currentThread().getName().equals("B")) {
flag = 3;
c3.signal();
}
if (Thread.currentThread().getName().equals("C")) {
flag = 1;
c1.signal();
}
} finally {
lock.unlock();
}
}
}
/**
* @Description: 多线程之间按顺序调用，实现A->B->C
* 三个线程启动，要求如下：
* <p>
* AA打印5次，BB打印10次，CC打印15次
* 接着
* AA打印5次，BB打印10次，CC打印15次
* ......来10轮
*/
public class ThreadOrderAccess {
public static void main(String[] args) {
ShareResource resource = new ShareResource();
new Thread(() -> {
for (int i = 1; i <= 10; i++) {
try {
resource.print();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}, "A").start();
new Thread(() -> {
for (int i = 1; i <= 10; i++) {
try {
resource.print();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}, "B").start();
new Thread(() -> {
for (int i = 1; i <= 10; i++) {
try {
resource.print();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}, "C").start();
}
}
