python3 PTA乙1039 到底买不买 (20分)

str_1 = list(input())
str_2 = list(input())
lack = 0
lack_list = []
for i in str_2:
    if i in lack_list:
        lack += 1
        continue
    for j in str_1:
        if i == j:
            str_1.remove(j)
            break
    else:
        lack += 1
        lack_list.append(i)
if lack == 0:
    print('Yes', len(str_1))
else:
    print('No', lack)
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转载自blog.csdn.net/AK47red/article/details/104307921