A+B is coming
- 寒假在家准备刷一下杭电的OJ，开始2000~2011，入门级，感觉还好，就开始了英文的入门题，当时看见十六进制觉得不难，还是年轻啊。自己只注意了一位数字的加减，忽略了多位加，比如 1a+2b,所以wrong answer，开始不明白，百度，看见了直接用hex流输入，三四行就ok。
A+B Coming
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 16659 Accepted Submission(s): 10548
Problem Description
Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal. _
Input
Input may contain multiple test cases. Each case contains A and B in one line.
A, B are hexadecimal number.
Input terminates by EOF.
Output
Output A+B in decimal number in one line.
Sample Input
1 9
A B
a b
Sample Output
10
21
21
Author
威士忌
Source
HZIEE 2007 Programming Contest
- 开始的wrong
#include<bits/stdc++.h>
using namespace std;
int main()
{
char a,b;int c,d;
while(cin>>a>>b)
{
c=a-'0';
d=b-'0';
if((c>=0&&c<=9))
c=c;
else if(c>=17&&c<=22)
c=c-7;
else c=c-39;
if((d>=0&&d<=9))
d=d;
else if(d>=17&&d<=22)
d=d-7;
else d=d-39;
cout<<c+d<<endl;
}
}
简单的accepted
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b;
while(cin>>hex>>a>>hex>>b)
{
cout<<a+b<<endl;
}
}
– 水平和大佬还是差距很大，继续吧，
