mysql搜索一个表然后更新这个表,给其中一个字段添加字符串

搜索一个表然后更新一个表

这样是不正确的

UPDATE appbricks_department 
SET rank = '2'  
WHERE parent_id in (SELECT id FROM appbricks_department WHERE parent_id IS NULL) ;

会报错

You can't specify target table 'student' for update in FROM clause

正确的写法

UPDATE appbricks_department 
SET rank = '2'  
WHERE parent_id in 
 (SELECT * FROM (SELECT id FROM appbricks_department WHERE parent_id IS NULL) a );

字符串拼接的语句

UPDATE test SET user= CONCAT(user,',phpchina')  WHERE id= '2';

最终我是用的语句记录一下:(感觉应该有一种更简单的,就是表自身进行连接,但是不会,等以后会了,再进行补充)

UPDATE student set certificateId = CONCAT(certificateId,"。"),visible = 0 WHERE idCard in (SELECT * FROM (SELECT idCard FROM student WHERE certificateId LIKE "V%" AND major_id in (2,5)) a) and major_id in (1,4) and certificateId LIKE "P%" and certificateId not LIKE "%。%"
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转载自blog.csdn.net/BrotherBear2008/article/details/81943473