Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,3,2] Output: 3
Example 2:
Input: [0,1,0,1,0,1,99] Output: 99
代码:
class Solution { public: int singleNumber(vector<int>& nums) { int i; if(nums.size()==1) return nums[0]; sort(nums.begin(), nums.end()); for(i=0; i<nums.size()-2; i+=3) { if(nums[i]!=nums[i+1]) return nums[i]; } return nums[i]; } };