判断是否是回文串

#include <stdio.h>
#include <iostream>

using namespace std;

int main()
{
	char arr[] = {'m','n','a','n','m'};
	char* pHead = arr;
	char* pTail = arr + (sizeof(arr) / sizeof(arr[0]) - 1); //将指针移动到数组末尾

	int flag = 1;
	while (pHead < pTail)
	{
		if (*pHead != *pTail)
		{
			flag = 0;
			break;
		}
		pHead++;
		pTail--;
	}

	if (flag == 0)
	{
		printf("不是回文\n");
	}
	else
	{
		printf("是回文\n");
	}

	system("pause");
	return 0;
}
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转载自blog.csdn.net/lpl312905509/article/details/93800852