1028 List Sorting (25point(s)) Easy only once

基本思想：

没什么难的，水题，重点在于审题；

关键点：

无；

#include<iostream>
#include<stdlib.h>
#include<stdio.h>
#include<vector> 
#include<string>
#include<math.h>
#include<algorithm>
#include<cstring>
using namespace std;
using std::vector;
const int maxn = 10010;

int n, c;
struct member {
	string name;
	int id;
	int grade;
};

vector<member>vec;

bool cmp(member a, member b) {
	if (c == 1) {
		return a.id < b.id;
	}
	else if (c == 2) {
		if (strcmp(a.name.c_str(), b.name.c_str()) < 0)
			return true;
		else if (strcmp(a.name.c_str(), b.name.c_str()) == 0)
			return a.id < b.id;
		else
			return false;
	}
	else {
		if (a.grade == b.grade)
			return a.id < b.id;
		else
			return a.grade < b.grade;
	}
}

int main() {
	scanf("%d %d", &n, &c);
	vec.resize(n);
	for (int i = 0; i < n; i++) {
		cin >> vec[i].id >> vec[i].name >> vec[i].grade;
	}
	sort(vec.begin(), vec.end(), cmp);
	for (int i = 0; i < n; i++) {
		printf("%06d %s %d\n", vec[i].id, vec[i].name.c_str(), vec[i].grade);
	}
	system("pause");
	return 0;
}