Description:
Given a string, you are supposed to output the length of the longest symmetric sub-string. For example, given Is PAT&TAP symmetric?, the longest symmetric sub-string is s PAT&TAP s, hence you must output 11.
Input Specification:
Each input file contains one test case which gives a non-empty string of length no more than 1000.
Output Specification:
For each test case, simply print the maximum length in a line.
Sample Input:
Is PAT&TAP symmetric?
Sample Output:
11
思路:
最大回文子串问题。回文串(palindromic string)是指这个字符串无论从左读还是从右读,所读的顺序是一样的;简而言之,回文串是左右对称的。
AC代码
#include <stdio.h>
#include <string.h>
#define maxn 1010 //最大子串长度为1000
int main()
{
char s[maxn];
int dp[maxn][maxn]={0};// dp[i][j]表示从i到j的字符串是否为回文子串,0表不是,1表是
gets(s);//空格也吸收
int len=strlen(s);//记录字符串长度
int ans=1;//记录最大长度
for(int i=0;i<len;i++)
{
dp[i][i]=1;
if(i<len-1&&s[i]==s[i+1])
{
dp[i][i+1]=1;
ans=2;
}
}//初始化长度为1和2的回文串
for(int L=3;L<=len;L++)//枚举长度为3到len的子串
{
for(int j=0;j+L-1<len;j++)//考察[j,j+L-1]的长度为L的子串是否为回文串
{
if(s[j]==s[j+L-1]&&dp[j+1][j+L-2]==1)//状态转移
{
dp[j][j+L-1]=1;
ans=L;
}
}
}
printf("%d",ans);
}