作业day01

作业1：使用while循环输入 1 2 3 4 5 6     8 9 10

使用while循环语句，并在count等于7的时候判断输出空格

while count < 10:
    if count != 7:
        print(count)
    else:
        print(" ")
    count = count+1

作业2：求1-100的所有数的和

定义两个值，count用于累加，while判断条件，sum用于count累加求和

count = 0
sum = 0

while count <= 100:
    sum = sum +count
    print(count)
    count = count+1
print(sum);

作业3：输出 1-100 内的所有奇数

其实就是1-100所有%2不为0的数字

count = 0

while count <= 100:
    if count%2 != 0:
        print(count)
    else:
        pass
    count = count+1

作业3：输出 1-100 内的所有偶数

其实就是1-100所有%2为0的数字

count = 0

while count <= 100:
    if count%2 == 0:
        print(count)
    else:
        pass
    count = count+1

作业4：求1-2+3-4+5 ... 99的所有数的和

1-100所有的奇数和减去所有的偶数和

count = 0
sum_js = 0
sum_os =0

while count <= 100:
    if count%2 != 0:
        sum_js = sum_js + count
        print(count)
    else:
        print(count)
        sum_os = sum_os + count
    count = count+1

sum_cy = sum_js - sum_os
print(sum_cy)

作业5：用户登陆（三次机会重试）

使用if条件语句判断，并且记录操作次数

count = 0
while count <3:
    name = input("请输入用户名");
    password =input("请输入密码");
    if name =="root" and password == "123":
        print("登陆成功");
        count = 3;
    else:
        count = count +1;
        if count !=3:
            print("剩余"+str(3-count)+"次机会");
        else:
            print("登陆失败，禁止登陆");