在论坛中出现的比较难的sql问题：3(row_number函数 分组查询)

原文: 在论坛中出现的比较难的sql问题：3(row_number函数 分组查询)

最近，在论坛中，遇到了不少比较难的sql问题，虽然自己都能解决，但发现过几天后，就记不起来了，也忘记解决的方法了。

所以，觉得有必要记录下来，这样以后再次碰到这类问题，也能从中获取解答的思路。另外，考虑到前2篇太长，看起来不太方便，所以拆分为第3篇

1、分组查询问题

http://bbs.csdn.net/topics/390619682?page=1#post-395835328

例子表结构数据如下：
id status date        price
1  1      2013-10-01  218
2  1      2013-10-02  218
3  0      2013-10-03  218
4  0      2013-10-04  238
5  0      2013-10-05  238
6  0      2013-10-06  238
7  0      2013-10-07  258
8  0      2013-10-08  258
9  0      2013-10-09  218


想获取的结果集一：
2013-10-01至2013-10-03  218
2013-10-04至2013-10-06  238
2013-10-07至2013-10-08  258
2013-10-09至2013-10-09  218


想获取的结果集二：
1  2013-10-01至2013-10-02  218
0  2013-10-03至2013-10-03  218
0  2013-10-04至2013-10-06  238
0  2013-10-07至2013-10-08  258
0  2013-10-09至2013-10-09  218

我的解法：

   
   
--drop table tb

create table tb( id int, status int, date varchar( 10),price int)

insert into tb
select 1, 1, '2013-10-01', 218 union all
select 2, 1, '2013-10-02', 218 union all
select 3, 0, '2013-10-03', 218 union all
select 4, 0, '2013-10-04', 238 union all
select 5, 0, '2013-10-05', 238 union all
select 6, 0, '2013-10-06', 238 union all
select 7, 0, '2013-10-07', 258 union all
select 8, 0, '2013-10-08', 258 union all
select 9, 0, '2013-10-09', 218 --union all
--select 10, 0, '2013-10-10', 218
go



--第一个结果集
;with t
as
(
select *,
row_number() over( partition by price order by id) as rownum,
min( id) over( partition by price) as min_id
from tb
),

tt
as
(
select id,
price,
a.date,
rownum - ( id - min_id) as interval
from t a
)

select min( date) + '至' + max( date) as date,
price
from tt
group by price, interval
order by 1
/*
date price
2013-10-01至2013-10-03 218
2013-10-04至2013-10-06 238
2013-10-07至2013-10-08 258
2013-10-09至2013-10-09 218
*/


--第2个结果集
;with t
as
(
select *,
row_number() over( partition by status,price order by id) as rownum,
min( id) over( partition by status,price) as min_id
from tb
),

tt
as
(
select id,
price,
a.date,
a.status,
rownum - ( id - min_id) as interval
from t a
)

select status, min( date) + '至' + max( date),price
from tt
group by status,price, interval
order by 2
/*
status date price
1 2013-10-01至2013-10-02 218
0 2013-10-03至2013-10-03 218
0 2013-10-04至2013-10-06 238
0 2013-10-07至2013-10-08 258
0 2013-10-09至2013-10-09 218
*/
  
  

2、查询出一段数据后判断记录里面的最大id,是否大于值a 查询语句如下：
http://bbs.csdn.net/topics/390619191

select top 200 id, ClassId,Name,Price,BoxContain,BoxLength,BoxWidth,BoxHeight,CName,EName,CPack,PhotoFolder,EPack,0.46*(round(((convert(decimal(10,2),BoxLength)*convert(decimal(10,2),BoxWidth) * convert(decimal(10,2),BoxHeight))/1000000),3))*35.32/BoxContain+Price/6*1.08 from ProductData where ClassId=101 and BoxContain >0 and BoxContain is not null and round(((convert(decimal(10,2),BoxLength)*convert(decimal(10,2),BoxWidth) * convert(decimal(10,2),BoxHeight))/1000000),3) >=0 And round(((convert(decimal(10,2),BoxLength)*convert(decimal(10,2),BoxWidth) * convert(decimal(10,2),BoxHeight))/1000000),3) <= 10000 and (0.46*(round(((convert(decimal(10,2),BoxLength)*convert(decimal(10,2),BoxWidth) * convert(decimal(10,2),BoxHeight))/1000000),3))*35.32/BoxContain+Price/6*1.08) >=10 and (0.46*(round(((convert(decimal(10,2),BoxLength)*convert(decimal(10,2),BoxWidth) * convert(decimal(10,2),BoxHeight))/1000000),3))*35.32/BoxContain+Price/6*1.08) <=1000 and EPack='Window Box' order by id asc
  
  

我的解法，适用于SQL Server 2000：

   
   
select *
from
(
select top 200 id, ClassId, Name,Price,BoxContain,BoxLength,BoxWidth,BoxHeight,CName,EName,CPack,PhotoFolder,EPack,
0.46*( round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3))* 35.32/BoxContain+Price/ 6* 1.08
from ProductData
where ClassId= 101 and BoxContain > 0 and BoxContain is not null
and round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3) >= 0
And round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3) <= 10000
and ( 0.46*( round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3))* 35.32/BoxContain+Price/ 6* 1.08) >= 10
and ( 0.46*( round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3))* 35.32/BoxContain+Price/ 6* 1.08) <= 1000
and EPack= 'Window Box'
order by id asc
)t
where
(
select max( id)
from
(
select top 200 id, ClassId, Name,Price,BoxContain,BoxLength,BoxWidth,BoxHeight,CName,EName,CPack,PhotoFolder,EPack,
0.46*( round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3))* 35.32/BoxContain+Price/ 6* 1.08
from ProductData
where ClassId= 101 and BoxContain > 0 and BoxContain is not null
and round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3) >= 0
And round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3) <= 10000
and ( 0.46*( round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3))* 35.32/BoxContain+Price/ 6* 1.08) >= 10
and ( 0.46*( round((( convert( decimal( 10, 2),BoxLength)* convert( decimal( 10, 2),BoxWidth) * convert( decimal( 10, 2),BoxHeight))/ 1000000), 3))* 35.32/BoxContain+Price/ 6* 1.08) <= 1000
and EPack= 'Window Box'
order by id asc
)t
) > a