python中使用excutemany执行update语句,批量更新

 
 

python中使用excutemany执行update语句,批量更新



# coding:utf8 import pymysql import logging connection
= pymysql.connect(host=HOST, port=3306, user=USER, password=PASSWORD, db=DATABASE,charset='utf8mb4',cursorclass=pymysql.cursors.DictCursor) cursor = connection.cursor() flag_List = ["A", "B", "C", "D"] # 存储flage的值 id_list = ["1", "2", "3", "4"] # 存储id的值 commit_id_list = [(flag_List[i], id_list[i]) for i in range(len(id_list))] # commit_id_list必须是list[tuple(),tuple()...]或tuple(tuple(),tuple()...)的形式 with connection.cursor() as cursor: try: sql = "update mydatabase SET flag=(%s) where id=(%s)" cursor.executemany(sql, commit_id_list) # commit_id_list上面已经说明 connection.commit() except: logging.exception("exception") connection.rollback() connection.close()

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转载自www.cnblogs.com/xiao-xue-di/p/11969138.html
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