高效的SQLSERVER分页查询

Sqlserver数据库分页查询一直是Sqlserver的短板,闲来无事,想出几种方法,假设有表ARTICLE,字段ID、YEAR...(其他省略),数据53210条(客户真实数据,量不大),分页查询每页30条,查询第1500页(即第45001-45030条数据),字段ID聚集索引,YEAR无索引,Sqlserver版本:2008R2

第一种方案、最简单、普通的方法: 

SELECT TOP 30 * FROM ARTICLE WHERE ID NOT IN (SELECT TOP 45000 ID FROM ARTICLE ORDER BY YEAR DESC, ID DESC) ORDER BY YEAR DESC,ID DESC

第二种方案: 

代码如下:

SELECT * FROM (SELECT TOP 30 * FROM (SELECT TOP 45030 * FROM ARTICLE ORDER BY YEAR DESC, ID DESC) f ORDER BY f.YEAR ASC, f.ID DESC) s ORDER BY s.YEAR DESC,s.ID DESC

平均查询100次所需时间:138S

第三种方案:

代码如下:

SELECT * FROM ARTICLE w1,   
(  
    SELECT TOP 30 ID FROM   
    (  
        SELECT TOP 50030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC  
    ) w ORDER BY w.YEAR ASC, w.ID ASC  
) w2 WHERE w1.ID = w2.ID ORDER BY w1.YEAR DESC, w1.ID DESC

平均查询100次所需时间:21S

第四种方案:

代码如下:

SELECT * FROM ARTICLE w1   
    WHERE ID in   
        (  
            SELECT top 30 ID FROM   
            (  
                SELECT top 45030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC  
            ) w ORDER BY w.YEAR ASC, w.ID ASC  
        )   
    ORDER BY w1.YEAR DESC, w1.ID DESC

平均查询100次所需时间:20S

第五种方案: 

代码如下:

SELECT w2.n, w1.* FROM ARTICLE w1, (SELECT TOP 50030 row_number() OVER (ORDER BY YEAR DESC, ID DESC) n, ID FROM ARTICLE ) w2 WHERE w1.ID = w2.ID AND w2.n > 50000 ORDER BY w2.n ASC

平均查询100次所需时间:15S

查询第1000-1030条记录

第一种方案: 

代码如下:

SELECT TOP 30 * FROM ARTICLE WHERE ID NOT IN(SELECT TOP 1000 ID FROM ARTICLE ORDER BY YEAR DESC, ID DESC) ORDER BY YEAR DESC,ID DESC

平均查询100次所需时间:80s

第二种方案:

代码如下:

SELECT * FROM  (   SELECT TOP 30 * FROM (SELECT TOP 1030 * FROM ARTICLE ORDER BY YEAR DESC, ID DESC) f ORDER BY f.YEAR ASC, f.ID DESC) s ORDER BY s.YEAR DESC,s.ID DESC

平均查询100次所需时间:30S

第三种方案: 

代码如下

SELECT * FROM ARTICLE w1,   
(  
    SELECT TOP 30 ID FROM   
    (  
        SELECT TOP 1030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC  
    ) w ORDER BY w.YEAR ASC, w.ID ASC  
) w2 WHERE w1.ID = w2.ID ORDER BY w1.YEAR DESC, w1.ID DESC

平均查询100次所需时间:12S

第四种方案: 

代码如下:

SELECT * FROM ARTICLE w1   
    WHERE ID in   
        (  
            SELECT top 30 ID FROM   
            (  
                SELECT top 1030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC  
            ) w ORDER BY w.YEAR ASC, w.ID ASC  
        )   
    ORDER BY w1.YEAR DESC, w1.ID DESC

平均查询100次所需时间:13S

第五种方案:

代码如下:

SELECT w2.n, w1.* FROM ARTICLE w1,(   SELECT TOP 1030 row_number() OVER (ORDER BY YEAR DESC, ID DESC) n, ID FROM ARTICLE) w2 WHERE w1.ID = w2.ID AND w2.n > 1000 ORDER BY w2.n ASC

平均查询100次所需时间:14S

     由此可见在查询页数靠前时,效率3>4>5>2>1,页码靠后时5>4>3>1>2,再根据用户习惯,一般用户的检索只看最前面几页,因此选择3 4 5方案均可,若综合考虑方案5是最好的选择,但是要注意SQL2000不支持row_number()函数,由于时间和条件的限制没有做更深入、范围更广的测试,有兴趣的

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转载自www.cnblogs.com/caiyt/p/11797644.html