Junbo-Kobe-python解方程式

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本文链接: https://blog.csdn.net/houlaos/article/details/102646154

2*x+1.2 = -1.2

高等数学:三明治定理

min = 0
max = 100
for a in range(20):
B=(min+max)/2
if 2*B+1.2>1.2:
max=B
else:
min=B
print(B)

2*x**2-4 +y =0

2*y**3 +x = 0

from sympy import *
x = Symbol(“x”)
y = Symbol(“y”)
print(solve([‘2x+4y-94’, ‘y+x-35’],[x,y]))

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转载自blog.csdn.net/houlaos/article/details/102646154