main函数传递参数

作业

main.c

#include<stdio.h>
#include<stdlib.h>
int sum(int N,int arr []);
int main (int argc ,char *argv[])
{
int result;
int ch[argc];
printf("%d\n",argc - 1);
for (int i = 0; i<argc; i++)
{
ch[i]=atoi(argv[i]);
result = sum (argc,ch);
}
printf ("the result is %d\n",result);
return;

}

sum.c

int sum(int N, int arr[])
{
int s = 0;
for (int i = 0; i<N;i++)
s +=arr[i];
return s;

}

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转载自www.cnblogs.com/waxxx/p/11640399.html