Add Digits

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 111 + 1 = 2. Since 2 has only one digit, return it.

 

public class Solution {
    public int addDigits(int num) {
        return (num - 1) % 9 + 1;
    }
}

 

猜你喜欢

转载自hcx2013.iteye.com/blog/2253554