java 如何编写多线程的代码

线程是干活的
所以线程一定是Thread,或者改线程实现Runnable接口
多线程是竞争关系,所以多个线程竞争同一个资源,也就是同一个对象
所以这个竞争对象发到Thread中
即:
// resources是竞争资源
Resources resources = new Resources();
Thread1 thread1 = new Thread1(resources);
Thread2 thread2 = new Thread2(resources);

thread1.start();
thread2.start();

----------------------------------------------------------------------
class Thread1 implements Runnable {
  Resources resources = null;
  Thread1(Resources resources) {
    this.resources = resources;
  }

  public void run() {
    //这个methodA方法时Resources里面的竞争资源方法
    resources.methodA();
  }
}

class Thread2 implements Runnable {
  Resources resources = null;
  Thread2(Resources resources) {
    this.resources = resources;
  }

  public void run() {
    //这个methodA方法时Resources里面的竞争资源方法
    resources.methodA();
  }

}

class Resources {
  private int count = 100;
  //多线程去干活了,它们争着抢着去执行竞争资源里面的方法,所以这个方法区域需要加锁
  public synchronized void methodA() {
    if(count > 0) {
      count--;
     }
  }
}

 例子:

package Thread;

public class MultiThread {

    public static void main(String[] args) {
        //resources就是竞争资源对象
        Resources resources = new Resources();
        Runnable1 runnable1 = new Runnable1(resources);

        for(int i = 0; i <100; i++) {
            // 这里是创建多线程去执行任务
            //多线程是竞争关系,所以多个线程竞争同一个资源,也就是同一个对象
            //所以这个竞争对象放到Thread中
            new Thread(runnable1,"Thread"+i).start();
        }
    }

}

class Resources {
    private int count = 100;
    
    //多线程去干活了,它们争着抢着去执行竞争资源里面的方法,所以这个方法区域需要加锁
    public synchronized  void methodA() {
        if(count > 0) {
            count--;
        }
        System.out.println(Thread.currentThread().getName() + "  " +"count:"+count);
    }
}

class Runnable1 implements Runnable {
    Resources resources = null;
    Runnable1(Resources resources) {
        this.resources = resources;
    }
    
    public void run() {
        //这个methodA方法时Resources里面的竞争资源方法
        resources.methodA();
    }
    
}

 .....

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转载自www.cnblogs.com/myseries/p/11595292.html