492. Construct the Rectangle - LeetCode

Description:

For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:

1. The given area won't exceed 10,000,000 and is a positive integer
2. The web page's width and length you designed must be positive integers.

Accepted

48,463

Submissions

99,081

 

Solution:

class Solution {
    public int[] constructRectangle(int area) {
        
        System.out.println(area);
        
        int [] a = new int[2];
        
        int Len = 1; //Len >= width
        
        int Diff = Integer.MAX_VALUE; 
        
        int Width = area/Len; 
        
            for(Len = 1; Len <=area ; Len++){

                if(area%Len ==0){

                     Width = area/Len; 
                    if(Len>=Width){
    
                    if(Len - Width <=Diff){
                        
                        Diff = Len - Width; 
                        
                        a[0] = Len ; 
                        
                        a[1] = Width; 
                    }
                   
                }

            }

        } 
        
        //System.out.println("Len = "+a[0] + " Width = "+a[1]);
            return a;  
    }
}