PAT A1035 Password (20)

AC代码

  • 注意创造函数条件中使用引用
  • 输出语句注意单复数
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>

using namespace std;

struct Usr {
    bool flag;
    char id[20];
    char pwd[20];
}usr[1010];

void modify(Usr& a) { //参数使用了引用&,可以对传入参数进行修改
    for(int i = 0; i < 10; i++) {
        char b = a.pwd[i];
        if(b == '1') {
            a.pwd[i] = '@';
            a.flag = 0;
        }
        if(b == '0') {
            a.pwd[i] = '%';
            a.flag = 0;
        }
        if(b == 'l') {
            a.pwd[i] = 'L';
            a.flag = 0;
        }
        if(b == 'O') {
            a.pwd[i] = 'o';
            a.flag = 0;
        }
    }
}
void init_flag(Usr& a) {
    a.flag = 1;
}

int main() {
    #ifdef ONLINE_JUDGE
    #else
        freopen("1.txt", "r", stdin);
    #endif // ONLINE_JUDGE
    int n;
    scanf("%d", &n); //输入密码数量
    for(int i = 0; i < n; i++) {
        scanf("%s %s", usr[i].id, usr[i].pwd);
    }
//    for(int i = 0; i < n; i++) {
//        printf("%s %s\n", usr[i].id, usr[i].pwd);
//    }
//    printf("------------------------------\n");
    int num = 0; //需要修改的密码数量
    //初始化flag
    for(int i = 0; i <= n; i++) {
        init_flag(usr[i]);
//        printf("init:%s %s %d\n", usr[i].id, usr[i].pwd, usr[i].flag);
        modify(usr[i]);
//        printf("%s %s %d\n", usr[i].id, usr[i].pwd, usr[i].flag);
        if(usr[i].flag == 0) {
            num++;
        }
    }
//    printf("------------------------------\n");
//    for(int i = 0; i < n; i++) {
//        printf("%s %s %d\n", usr[i].id, usr[i].pwd, usr[i].flag);
//    }
//    printf("------------------------------\n");
//    printf("%d\n", num);
    if(num != 0) {
        printf("%d\n", num);
        for(int i = 0; i <= n; i++) {
            if(usr[i].flag == 0) {
                printf("%s %s\n", usr[i].id, usr[i].pwd);
            }
        }
    } else if(n == 1){
        printf("There is %d account and no account is modified", n);
    } else if(n > 1) {
        printf("There are %d accounts and no account is modified", n);
    }
    return 0;
}

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转载自www.cnblogs.com/isChenJY/p/11374208.html