(Easy) Fibonacci Number LeetCode

Description

The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,

F(0) = 0,   F(1) = 1
F(N) = F(N - 1) + F(N - 2), for N > 1.

Given N, calculate F(N).

Example 1:

Input: 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.

Example 2:

Input: 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.

Example 3:

Input: 4
Output: 3
Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.

Note:

0 ≤ N ≤ 30.

Solution

class Solution {
    public int fib(int N) {
        
         
        
        if(N==0){
            return 0;
        }
        
        if(N==1){
            return 1;
        }
        
        int[] dp = new int[N+1];
        
        dp[0]=0;
        dp[1]=1;
        
        for(int i =2; i<=N; i++){
            
            dp[i]=dp[i-1]+dp[i-2];
        }

        return dp[N];
    }
}