BZOJ 4883: [Lydsy1705月赛]棋盘上的守卫 最小生成树 + 建模

Code: 

#include <cstdio>
#include <algorithm> 
#include <string> 
using namespace std;  
typedef long long ll; 
const int maxn=200003;   
namespace IO { 
    inline void setIO(string s) {
        string in=s+".in"; 
        freopen(in.c_str(),"r",stdin); 
    }
};  
struct Edge { 
    int u,v; 
    ll c; 
}ed[maxn];     
bool cmp(Edge a,Edge b) {
    return a.c < b.c; 
}
int p[maxn],tag[maxn];   
int find(int x) {
    return p[x]==x?x:p[x]=find(p[x]);    
}
int main() {
    // IO::setIO("input"); 
    int n,m,i,j,edges=0; 
    scanf("%d%d",&n,&m);  
    for(i=1;i<=n+m+1;++i) p[i]=i;   
    for(i=1;i<=n;++i) for(j=1;j<=m;++j) {
        ++edges;    
        scanf("%lld",&ed[edges].c),ed[edges].u=i,ed[edges].v=j+n;           
    }     
    sort(ed+1,ed+1+edges,cmp);  
    ll ans=0;        
    for(i=1;i<=edges;++i) {
        int x=ed[i].u,y=ed[i].v; 
        ll val=ed[i].c;   
        x=find(x),y=find(y); 
        if(x==y && !tag[x]) tag[x]=1, ans+=val;                                                   
        else if(x!=y&&(!tag[x]||!tag[y])) ans+=val, p[x]=y, tag[y]|=tag[x];   
    } 
    printf("%lld\n",ans); 
    return 0; 
}

  

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转载自www.cnblogs.com/guangheli/p/11294549.html
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