ABAP算法题：海盗报数问题。

题目:有一艘海盗船上面有30个海盗，分别为海盗1-30号忽然海盗船撞上了冰山，船上只能留下一个人，船长命令大家循环数数，数到7和7的倍数的人，跳到海里去。

分析： 没什么好分析的。

输入海盗人数，输入死亡数字，输出海盗死亡顺序。

SELECTION-SCREEN BEGIN OF BLOCK b0.
PARAMETERS: p_number   TYPE i OBLIGATORY.
PARAMETERS: p_keyval   TYPE i OBLIGATORY.
SELECTION-SCREEN END OF BLOCK b0.
*
**
TYPES: BEGIN OF person,
         index TYPE i,
         numbr TYPE i,
       END OF person.
DATA :t_person TYPE TABLE OF person.

DATA last_number TYPE i.

t_person = VALUE #( FOR i = 1 UNTIL i > p_number ( index = i ) ).

DO.
  IF lines( t_person ) < 2.EXIT.ENDIF.

  LOOP AT t_person ASSIGNING FIELD-SYMBOL(<s_person>).
    <s_person>-numbr = COND #( WHEN last_number = p_keyval THEN 1 ELSE last_number + 1 ).
    last_number = <s_person>-numbr.
    IF <s_person>-numbr = p_keyval.
      WRITE: / 'index' ,<s_person>-index,'dead! '.
      DELETE t_person.
    ENDIF.
  ENDLOOP.
ENDDO.

READ TABLE t_person ASSIGNING <s_person> INDEX 1.
WRITE :/ 'index', <s_person>-index,'alive '.