pre_exam_exercise1

def rearrange(number):
    str1=str(number)
    list1=[]
    for i in str1:
        if i!='0':
            list1.append(i)
    list2=sorted(list1)    
    str2=''.join(str(i) for i in list2)
    number=int(str2)
    return number


number=rearrange(10029001)
print(number)


#改良版
def rearrange(number):
    list1=[i for i in str(number) if i!='0']
    #list1=list(str1.replace('0',''))
    str2=''.join(sorted(list1))
    return (int(str2))


number=rearrange(10029001)
print(number)

题目：

Returns an integer consisting of all nonzero digits in "number", from smallest to largest.
You can assume that "number" is a valid strictly positive integer.
>>> rearrange(1)

1

>>> rearrange(200)

2

>>> rearrange(395)

359

>>> rearrange(10029001)

1129

>>> rearrange(301302004)

12334

>>> rearrange(9409898038908908934890)

33448888889999999

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