关于Vigenere爆0总结

爆0
考试经历如下
首先,我用昨天的不定参数写了一个debug

模板如下

#include<bits/stdc++.h>
using namespace std;
#define print(type,data) #data , type , data
#define CHAR 0
#define INT 1
#define LONG 2
#define LONG_LONG 3
#define FLOAT 4
#define DOUBLE 5
#define STRING 6
//定义类型
/*例子:
#define MYTYPE 7
*/
#pragma message("Define new type of debugable data here")

//添加类&结构体
/*例子:
struct mytype{
.....
};
*/
#pragma message("Define new class&struct here")

void debugPrint(int line,int dataNum,...){//follow as name-type-pointer
#ifndef ONLINE_JUDGE
fprintf(stderr,"Debug message on line %d:\n",line);
va_list dataPtr;
va_start(dataPtr,dataNum);
#pragma message("Add temps here")
/*添加临时变量位置(供调用数据)
例子:
mytype temp_mytype;
*/
while(dataNum--){
fprintf(stderr,"    \"%s\"",va_arg(dataPtr,const char*));
switch(va_arg(dataPtr,int)){
case CHAR:
fprintf(stderr,"(char)=\'%c\'",va_arg(dataPtr,int));
break;
case INT:
fprintf(stderr,"(int)=%d",va_arg(dataPtr,int));
break;
case LONG:
fprintf(stderr,"(long)=%ld",va_arg(dataPtr,long));
break;
case LONG_LONG:
fprintf(stderr,"(long long)=%lld",va_arg(dataPtr,long long));
break;
case FLOAT:
fprintf(stderr,"(float)=%f",va_arg(dataPtr,double));
break;
case DOUBLE:
fprintf(stderr,"(double)=%lf",va_arg(dataPtr,double));
break;
case STRING:
fprintf(stderr,"(string)=\"%s\"",va_arg(dataPtr,char*));
break;
#pragma message("Add new type to debug data here")
/*添加数据类型处理代码
例子:
case MYTYPE:
temp_mytype=va_arg(dataPtr,mytype);
fprintf(stderr,"(mytype)= ..... ,temp_mytype);
break;
*/ 
default:
fprintf(stderr,"(UNKNOW)=<WARNING:UNKNOW TYPE OF DATA>");
}
fprintf(stderr,"\n");
}
fprintf(stderr,"End debug message.\n\n");
#endif
}
//你的代码
#define maxN 10000
void input(){

}

void solve(){

}

int main(){
#ifndef ONLINE_JUDGE
freopen("filename.txt","r",stdin);//标准输入重定向
freopen("filename.dbg.txt","w",stderr);//错误输出重定向(用来调试程序)
#endif
input();
solve();
return 0;
}

这个玩意用法如下:

int i=10356;
char c='R';
char str[10]="Unreal Enging 4.22";

如果是这些东西要输出就用这个

debugPrint(__LINE__,3,print(INT,i),print(CHAR,c),print(STRING,str));

不嫌麻烦也可以用这个

debugPrint(__LINE__,3,"i",INT,i,"c",CHAR,c,"str",STRING,str);

显示结果如下(假设调试代码在第83行)

Debug message on line 83:
"i"(int)=10356
"c"(char)='R';
"str"(string)="Unreal Enging 4.22"
End debug message.

然后就用这个写程序
一开始就发现规律:
**以a为0计算: 明码+密码再对26取余就得密码**
那就好算了
表都不用打

一开始
样例没过,输入问题
输入一改就过了
我甚至写了一个刷数据的
(代码就是把一个减号该了加号)
然后似乎AC

然后第二题美滋滋
然后
然后
然后GG

(第一个RE是把ONLINE_JUDGE打成UNLINE_JUDGE导致的)
然后下载样例,
得出一个结论:
两个数据是以回车间隔的,而我是以空格分隔读入的
然后大改,
结果本地情况:
AC
OJ:
80
俩WA
然后

========[vigenere9.out]=========
Expected    |    Yours
wiguiynlznsdmjwabkzxlzepyvAZJDVWEWWCDPDNBSJYWLIMYBPDrtuwsskdp
<

==============================
========[vigenere8.out]=========
Expected    |    Yours
vjihrjxlurwleuwvueanvyajglATWDRKGCQPOYQESBYDSLBDCBLHucfhqnsha
<

==============================
========[vigenere4.out]=========
Expected    |    Yours
iohrvzilldmyuatdhluxxpykgmFPTXGJJBKWSYRBFJSVVNWIEKDNrvehhziuq
<

==============================
========[vigenere10.out]=========
Expected    |    Yours
msfxvxrlgfkdfussyiwvnjnldzFJTPGFRSMMQCGABXDXKPBDYEYMdujhmwmym
<

==============================
========[vigenere3.out]=========
Expected    |    Yours
aqroiftkxnkcmcdaurfwjzwoyoPMGDRIVLIAKABYSPDUHXUMWMNKebpgtjgyi
<

==============================
========[vigenere2.out]=========
Expected    |    Yours
hfnosmkstxrpxycwucdhbzhimgEMNRLJRSWQOWXBVTBCGAYGHLFDlmqkiqrvp
<

==============================
========[vigenere7.out]=========
Expected    |    Yours
wpukmrofcnwtkhsbypmxddkkefGHYRWMOTQHEPYVMJUDAROZFFMMghijatyoq
<

==============================
========[vigenere1.out]=========
Expected    |    Yours
abceefgiijkmmnoqqrsuuvwyyzACCDEGGHIKKLMOOPQSSTUWWXYA
<

==============================
========[vigenere5.out]=========
Expected    |    Yours
hbqflnjlsnxoqwwwqfuacyahcmDFLLLFUJPRNPWRBSUAAAUJYEGCelgqhjppp
<

==============================

那就是
不够鲁棒
鲁棒后AC
MMP