Java有趣的自己调用自己

class Test2
{
    private Test2 a;
    //private static Test2 a=new Test2();
    public static void main(String[] args)
   {
        Test2 t = new Test2(); 
    }
 public Test2 getA() {
  return a;
 }
 public void setA(Test2 a) {
  this.a = a;
 }

}

  第一种情况,自己调用自己,并迭代;但没有new出新对象,正常

class Test3
{
    private Test3 a=new Test3();
    //private static Test3 a=new Test3();
    public static void main(String[] args)
   {
        Test3 t = new Test3(); 
    }
 public Test3 getA() {
  return a;
 }
 public void setA(Test3 a) {
  this.a = a;
 }

} 

 第而种情况,自己调用自己,并迭代,生成新的对象;
结果 Exception in thread "main" java.lang.StackOverflowError;

class Test4
{
    private static Test4 a=new Test4();
    public static void main(String[] args)
   {
        Test4 t = new Test4();
        System.out.println(t.getA());
        System.out.println(t.getA().getA());
        System.out.println(t.getA().getA().getA());
    }
	public Test4 getA() {
		return a;
	}
	public void setA(Test4 a) {
		this.a = a;
	}

} 

第三种情况,没有报错,因为生成了静态对象,结果

com.b5map.Test4@6084fa6a
com.b5map.Test4@6084fa6a
com.b5map.Test4@6084fa6a

总结:static关键字,只保留自己唯独一份的变量;而且对自身的引用始终是自己;

class Test3
{
    private Test3 a=new Test3();
    //private static Test3 a=new Test3();
    public static void main(String[] args)
   {
        Test3 t = new Test3(); 
    }
 public Test3 getA() {
  return a;
 }
 public void setA(Test3 a) {
  this.a = a;
 }

} 

 第而种情况,自己调用自己,并迭代,生成新的对象;
结果 Exception in thread "main" java.lang.StackOverflowError;

class Test4
{
    private static Test4 a=new Test4();
    public static void main(String[] args)
   {
        Test4 t = new Test4();
        System.out.println(t.getA());
        System.out.println(t.getA().getA());
        System.out.println(t.getA().getA().getA());
    }
	public Test4 getA() {
		return a;
	}
	public void setA(Test4 a) {
		this.a = a;
	}

} 

第三种情况,没有报错,因为生成了静态对象,结果

com.b5map.Test4@6084fa6a
com.b5map.Test4@6084fa6a
com.b5map.Test4@6084fa6a

总结:static关键字,只保留自己唯独一份的变量;而且对自身的引用始终是自己;

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转载自alafqq.iteye.com/blog/2287043
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