自学python 第二天

1. if基本语句

  if 条件:

    内部代码块

  else:

     .. . .. . .

    print(“........”)

    if 1 == 1 :

      print(“a会所”)

      print(“b会所”)

  else:

    print(“c会所”)

2. if 支持嵌套

  if   1 == 1:

    if   2 == 2:

      print(“a会所”)

      print(“b会所”)

    else:

      print:(“c会所”)

3.if    elif       (elif=else  if)

  inp =input(“请输入会员等级:”)

  if  inp ==‘高级会员’:

    print (“1”)

  elif inp ==“白金会员”:

    print(“2”)

  elif inp ==“铂金会员”

    print (“3”)

  else:(“4”)

    print(“正在加载中”)

 补充:pass(代表:当条件成立后不做任何操作,代指空代码,无意义,仅仅用于表示代码块)

  if  1 == 1

   pass

else:

  print(“0.0”)

字符窜 (引号):

  name = “alex”

  name = “我是IIS”

  .. .....

   字符窜中 含有加法:

        n1 = “alex”

        n2 = “sb”

        n3 = n1   +    n2

      print (n3)

    alexsb

  字符窜中 含有乘法 :

            n1 =“alex”

            n2 = n1 * 10

      print(n2)

  alexalexalexalexalexalexalexalexalexalex

数字:

  age = 16 (没有引号)

      加:

        a1 = 10

        a2 = 20

        a3 = a1 + a2

      减:

        a3 = a1  - a2

      乘:

        a3 = a1 * a2

      除:

        a3 = a1 / a2

  特殊法:

    a3 = 4 ** 4                                                                                      

    a3 = 39 % 8     #获得39除以8的余数

    a = 13

    temp = a  % 2

    if  tmp == 0:

        print(“偶数”)

    else:

    print (“奇数”)

  while 的用法

import  count

count = 0

while count < 10:

    print(count)

    # count = 100

    count = count + 1

print(123)

练习: 1.使用while循环输入1 2 3 4 5 6 8 9 10

       n = 1

       while n < 11:

          if  n =7:

            pass

          else:

            print(n)

          n = n + 1

        print (“----end----”)

    2.求1-100的所有数的和

         n = 1

       s = 0

       while n < 101:

          print(n)

        n = n + 1

        s = s + n

      print(s)

    3.求1-100内所有的奇数

          n = 1

       while n < 101:

          temp = n % 2

          if  temp ==0

            pass

          else:

            print(n)

          n = n + 1

        print (“----end----”)

    4.输出1-100内所有偶数

        n = 1

       while n < 101:

          temp = n % 2

          if  temp !=0

            pass

          else:

            print(n)

          n = n + 1

        print (“----end----”)

    5.求1 - 2 + 3 - 4 + 5 . . . 99 的所有数的和

      n = 1

      s = 0      #s 是之前所有数的总和

      while n < 100:

          temp = n %2

          if temp == 0:

            s = s - n

          else:

            s = s + n

          n = n + 1

        print(s)

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转载自www.cnblogs.com/YCJW/p/11042942.html