一本通 1274：【例9.18】合并石子

合并石子

状态转移方程：f_min[i][i] = 0, f_min[i][j] = min(f_min[i][k] + f_min[k+1][j] + sum[j] - sum[i-1];

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Code:

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
//Mystery_Sky
//
#define INF 0x3f3f3f3f
#define M 5500
int f_min[M][M];
int n, sum[M];
int main() {
    memset(f_min, INF, sizeof(f_min));
    scanf("%d", &n);
    int x;
    for(int i = 1; i <= n; i++) {
        scanf("%d", &x);
        sum[i] = sum[i-1] + x;
        f_min[i][i] = 0;
    }
    for(int i = n; i >= 1; i--) {
        for(int j = i + 1; j <= n; j++) {
            for(int k = i; k <= j - 1; k++) {
                f_min[i][j] = min(f_min[i][j], f_min[i][k] + f_min[k+1][j] + sum[j] - sum[i - 1]);
            }
        }
    }
    printf("%d\n", f_min[1][n]);
    return 0;
}