截取指定字符串

想要获取invite_uuid=之后的那一串字符：

url = "http://www.baidu.com/public_share?rule_type=member&invite_uuid=72665347-35b1-4326-b37d-078d4f8f3f73&"
print (url.index("&"))
r1 =url[url.index("&")+1:-1]
print(r1)
r1.index('=')
print(r1[r1.index('=')+1:-1])

返回：72665347-35b1-4326-b37d-078d4f8f3f7


方法二：正则表达式：很好用

string = "xxxxxxxxxxxxxxxxxxxxxxxx entry '某某内容' for aaaaaaaaaaaaaaaaaa"

result = re.findall(".*entry(.*)for.*", string)

for x in result:
    print(x)

》》》'某某内容'
但是此方法如果在string字符串中有多个，就只会取最后一个的