LeetCode-445-两数相加II-C语言

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */

typedef struct ListNode Node;

/* 反转链表 */
Node *reverse(Node *head){
    Node node;
    node.next = NULL;
    Node *last = NULL;
    
    while(head){
        last = head;
        head = head->next;
        
        last->next = node.next;
        node.next = last;
    }
    
    return node.next;
}

/* 链表相加 */
struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2){
    Node node;/* 创建一个node.next为头节点的链表,将新的节点添加到该节点,返回该链表的反转链表即可 */
    node.next = NULL;
    Node *rear = &node;
    int flag = 0;
    int tmp = 0;
    Node *last = NULL;
    
    l1 = reverse(l1);
    l2 = reverse(l2);
    
    while(l1 || l2 || flag){
        tmp = (l1 ? l1->val : 0) + (l2 ? l2->val : 0) +flag;
        flag = 0;
        if(tmp >= 10){
            tmp -= 10;
            flag = 1;
        }
        
        last = l1 ? l1 : l2;
        if(!last){
            last = (Node *)malloc(sizeof(Node));
        }
        
        last->val = tmp;
        
        if(l1)
            l1 = l1->next;
        if(l2)
            l2 = l2->next;
    
        rear->next = last;
        rear = rear->next;
        rear->next = NULL;
    }
    
    return reverse(node.next);
}


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转载自blog.csdn.net/weixin_36094222/article/details/90045470