第四次作业 ——吴靖瑜

习题1:设计一个本月份日历,输出格式如下:
要求:
1.初始化start_day,end_day两个日期
from datetime import datetime
start_day=datetime(2019,4,1)
end_day=datetime(2019,4,30)
其它时间数据生成要用datetime或date模块的方法编程实现
2.不能使用calendar模块生成
代码:

from
datetime import datetime start_day=datetime(2019,4,1) end_day=datetime(2019,4,30) print(start_day.strftime('\t\t\t%Y/%m'))#输出年份与月份 print("星期日\t星期一\t星期二\t星期三\t星期四\t星期五\t星期六") first_day=start_day.weekday() day=30 #2019年4月有30天 count = 0 #定义一个计数器 k = 0 while k <= first_day: #每个月的开始第一周前面的空格数 k += 1 print(" \t",end=" ") count += 1 if (count % 7 == 0):print(" \n") # count=7 进行换行 p = 1 while p <= day: #显示天数 print(p,"\t",end="") #打印 table 不换行 p += 1 count += 1 if(count % 7 == 0):print("\n") #count=7 进行换行

习题2:

设计题2:

1.参考“三国演义”词频统计程序,实现对红楼梦出场人物的频次统计。
2.(可选)
将红楼梦出场人物的频次统计结果用词云显示。

 代码:

import jieba
excludes = {"怎么","快去","什么","一个","我们","那里","你们","如今","说道","知道","起来",
            "这里","出来","他们","众人","有些","说道","下来","不如","后来","里面","然后","一面","今儿",
            "自己","这么","这个","别处","东西","好看","舍得","远远","那里","这里",
            "各自","一边","一面","一个","只管","只觉","银子","俺们","咱们","回来","不能","天天"}
txt = open("红楼梦.txt", "r", encoding='utf-8').read()
words  = jieba.lcut(txt)
count = {} 
for word in words:
    if len(word) == 1:
        continue
    elif word == "宝哥哥" or word == "宝二爷"or word=="怡红公子"or word=="绛洞花王":
        rword = "贾宝玉"
    elif word == "林姑娘" or word == "林妹妹"or word=="潇湘妃子" or word=="颦颦":
        rword = "林黛玉"
    elif word == "宝钗" or word == "宝姐姐" or word=="蘅芜君" or word=="宝丫头" or word=="宝姑娘":
        rword = "薛宝钗"
    elif word == "凤哥儿" or word == "琏二奶奶" or word=="凤辣子" or word=="凤姐":
        rword = "王熙凤"
    elif word == "三姑娘" or word == "蕉下客" or word=="玫瑰花":
        rword = "贾探春"
    elif word == "史大姑娘" or word == "云妹妹"or word=="枕霞旧友":
        rword = "史湘云"
    elif word == "二姑娘" or word == "二木头" or word=="菱洲":
        rword = "贾迎春"
    elif word == "四姑娘" or word == "四丫头" or word=="藕榭" or word=="藕丫头":
        rword = "贾惜春"
    elif word == "秦氏" or word == "蓉大奶奶" or word=="可儿" or word=="兼美":
        rword = "秦可卿"
    else:
        rword = word
    count[rword] = count.get(rword,0)+1 
for word in excludes:
    del(count[word])
items = list(count.items())
items.sort(key=lambda x:x[1], reverse=True)
for i in range(25): 
    word, count= items[i] 
    print ("{0:<10}{1:>6}".format(word, count))

 

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转载自www.cnblogs.com/taetaewu/p/10836199.html
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