Java通用的response响应内容格式(json)

response回执通用格式,后端将数据返回给前端的数据格式
返回的是对象,也可以是map或json
代码如下:

import java.util.HashMap;
import java.util.Map;

public class ResponseUtil {
    public static Object ok() {
        Map<String, Object> obj = new HashMap<String, Object>();
        obj.put("errno", 0);
        obj.put("errmsg", "成功");
        return obj;
    }

    public static Object ok(Object data) {
        Map<String, Object> obj = new HashMap<String, Object>();
        obj.put("errno", 0);
        obj.put("errmsg", "成功");
        obj.put("data", data);
        return obj;
    }

    public static Object ok(String errmsg, Object data) {
        Map<String, Object> obj = new HashMap<String, Object>();
        obj.put("errno", 0);
        obj.put("errmsg", errmsg);
        obj.put("data", data);
        return obj;
    }

    public static Object fail() {
        Map<String, Object> obj = new HashMap<String, Object>();
        obj.put("errno", -1);
        obj.put("errmsg", "错误");
        return obj;
    }

    public static Object fail(int errno, String errmsg) {
        Map<String, Object> obj = new HashMap<String, Object>();
        obj.put("errno", errno);
        obj.put("errmsg", errmsg);
        return obj;
    }

    public static Object badArgument(){
        return fail(401, "参数不对");
    }

    public static Object badArgumentValue(){
        return fail(402, "参数值不对");
    }

    public static Object updatedDateExpired(){
        return fail(403, "更新数据已经失效");
    }

    public static Object unlogin(){
        return fail(501, "请登录");
    }

    public static Object serious(){
        return fail(502, "系统内部错误");
    }

    public static Object unsupport(){
        return fail(503, "业务不支持");
    }
    
    public static Object unregist(){
        return fail(504, "用户未注册");
    }
}

若哪里不足,请大家多多指点!!!

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转载自blog.csdn.net/yijigu_JUN/article/details/89385072
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