题目链接:https://leetcode-cn.com/explore/interview/card/top-interview-quesitons-in-2018/275/string/1144/
题目描述
编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
示例 1:
输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
代码
class Solution {
public:
void reverseString(vector<char>& s) {
if(s.size()<=1) return;
int begin = 0;
int end = s.size() -1;
while(begin < end){
char tmp = s[begin];
s[begin] = s[end];
s[end] = tmp;
++ begin;
-- end;
}
}
};