生产者消费者之包子顾客问题

现有一个包子铺, 有两名员工在不停的做包子, 一秒钟做一个, 当包子铺的包子总数达到100的时候, 停止做包子. 现有多名顾客同时吃包子, 当包子已经吃完的时候, 等着员工生产包子, 当有了包子就继续吃

 

public class test {
        static int num =0;
	public static void main(String[] args) {

	Runnable r = new Runnable() {
			@Override
			public void run() {
				while(true) {
					synchronized (Lock.class) {
						if (num<100) {
							num++;
							System.out.println(Thread.currentThread().getName()+"做了第一个包子");
						}else {
							try {
								Thread.sleep(1000);
							} catch (InterruptedException e) {
								e.printStackTrace();
							}
						}
						
					}
					
				}
				
			}
		};
		Thread t1 = new Thread(r, "工人一");
		Thread t2 = new Thread(r, "工人二");
			
		Runnable r2 = new Runnable() {
			public void run() {
				while(true) {
					synchronized (Lock.class) {
						if (num>0) {
							System.out.println(Thread.currentThread().getName()+"个顾客吃了一个包子");
							num--;
						}else {
							System.out.println("包子没啦,赶紧做,我要吃包子...");
							try {
								Thread.sleep(1000);
							} catch (InterruptedException e) {
								e.printStackTrace();
							}
						}
						
					}
				}
			}
		};
		
		Thread c1 = new Thread(r2,"顾客一");
		Thread c2 = new Thread(r2, "顾客二");
		t1.start();
		t2.start();
		c1.start();
		c2.start();
	}