SWUSTOJ #287 one + two = 3

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题目

读入两个小于100的正整数A和B，计算A+B。需要注意的是：A和B的每一位数字由对应的英文单词给出。

输入

测试输入包含若干测试用例，每个测试用例占一行，格式为"A + B ="，相邻两字符串有一个空格间隔。当A和B同时为0时输入结束，相应的结果不要输出。

输出

对每个测试用例输出1行，即A+B的值。

样例输入

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

样例输出

3
90
96

源代码

#include <stdio.h>
#include <string.h>

int num1(char a[])
{
	if(strcmp(a,"one") == 0) return 1;
	else if(strcmp(a,"two") == 0) return 2;
	else if(strcmp(a,"three") == 0) return 3;
	else if(strcmp(a,"four") == 0) return 4;
	else if(strcmp(a,"five") == 0) return 5;
	else if(strcmp(a,"six") == 0) return 6;
	else if(strcmp(a,"seven") == 0) return 7;
	else if(strcmp(a,"eight") == 0) return 8;
	else if(strcmp(a,"nine") == 0) return 9;
	else if(strcmp(a,"zero") == 0) return 0;
}
int num2(char a[])
{
	if(strcmp(a,"one") == 0) return 1;
	else if(strcmp(a,"two") == 0) return 2;
	else if(strcmp(a,"three") == 0) return 3;
	else if(strcmp(a,"four") == 0) return 4;
	else if(strcmp(a,"five") == 0) return 5;
	else if(strcmp(a,"six") == 0) return 6;
	else if(strcmp(a,"seven") == 0) return 7;
	else if(strcmp(a,"eight") == 0) return 8;
	else if(strcmp(a,"nine") == 0) return 9;
	else if(strcmp(a,"zero") == 0) return 0;
}
int main()
{
	char a[20];
	while(1)
	{
		int sum=0, sum1=0, sum2=0;
		scanf("%s", a);
		sum1=num1(a);
		scanf("%s", a);
		if(strcmp(a,"+") != 0)
		{
			sum1 = sum1*10 + num1(a);
			scanf("%s", a);
		}
		scanf("%s", a);
		sum2 = num2(a);
		scanf("%s", a);
		if(strcmp(a,"=") != 0)
		{
			sum2 = sum2*10 + num2(a);
			scanf("%s", a);
		}
		sum = sum1 + sum2;
		if(sum == 0)
			break;
		else
			printf("%d\n", sum);
	}
	return 0;
}