题目描述:有两个日期,求两个日期之间的天数,若连续,规定天数为两天
输入格式:多组数据,每个数据两行,形式为YYYYMMDD
输出格式:一行,差值
样例输入:
20130101
20130105
样例输出:
5
注意代码中每月天数的存储结构和闰年的判断
#include<cstdio>
int month[13][2]={{0,0},{31,31},{28,29},{31,31},{30,30},{31,31},{30,30},
{31,31},{31,31},{30,30},{31,31},{30,30},{31,31},};
bool isleap(int year){ //判断是否是闰年
return (year%4==0&&year%100!=0)||(year%400==0);
}
int main(){
int time1,y1,m1,d1;
int time2,y2,m2,d2;
while(scanf("%d%d",&time1,&time2)!=EOF){
if(time1>time2){ //第一个日期晚于第二个日期,则交换
int temp=time1;
time1=time2;
time2=temp;
}
y1=time1/10000,m1=time1%10000/100,d1=time1%100;
y2=time2/10000,m2=time2%10000/100,d2=time2%100;
int ans=1;//记录结果
while(y1<y2||m1<m2||d1<d2){
d1++;//天数加一
if(d1==month[m1][isleap(y1)]+1){ //满当月天数
m1++;
d1=1;
}
if(m1==13){ //月份满12个月
y1++;
m1=1;
}
ans++;//累计
}
printf("%d\n",ans);
}
return 0;
}