JS 输入日期,实现计算下一日

NaN

所以,可以根据这样的特性,判断数是否为 NaN 。

在第二日计算问题,当日期为月末时,使用如下方式可以使其加一

var currentDate = new Date();
var nextDate = +currentDate + 1000*60*60*24;
nextDate = new Date(nextDate);
console.log(nextDate);

例子

<form id="dateForm">
    <input type="date" id="date" placeholder="请输入日期">
    <button type="button" id="btn" onclick="computed()">计算第二日</button>
    <p id="result"></p>
</form>
<script type='text/javascript'>
    function computed() {
        var currentDate = document.getElementById('date').value;
        var result = document.getElementById('result');
        result.innerHTML= '';
        if(currentDate.value == ""){
            window.alert('请输入计算日期!'.currentDate.value);
            return false;
        }
       currentDate = new Date(currentDate);
       currentDate = +currentDate + 1000*60*60*24;
       currentDate = new Date(currentDate);
       var nextDate = currentDate.getFullYear()+"-"+(currentDate.getMonth()+1)+"-"+currentDate.getDate();
       var year = currentDate.getFullYear();
       if(year !== year){
         window.alert('请选择日期!');
         return false;
       }

       result.innerHTML = "第二日:" + nextDate;
    }
</script>

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转载自blog.csdn.net/Lyj1010/article/details/88775979
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