两个线程题

一个线程先打印Thread-1、Thread-2、Thread-3、 Thread-4、Thread-5
另一个线程再打印Thread-6、Thread-7、Thread-8、Thread-9、Thread-10

static SingletonDemo1 s = new SingletonDemo1();
    	/*public static SingletonDemo1 in=new SingletonDemo1();;
    	private SingletonDemo1(){}
    	public static SingletonDemo1 getSingletonDemo1(){
    		return in;
    	}*/
    	public static void main(String[] args) {
    		
    		 new Thread(new Runnable() {
    	            @Override
    	            
    	            public void run() {
    	            	  synchronized (s){
    	                for(int i = 0;i<5;i++){
    	                  
    	                        System.out.println("Thread-"+i);
    	                        
    	                    }
    	                }
    	            }
    	        }).start();
    	        //线程2
    	        new Thread(new Runnable() {
    	            @Override
    	            public void run() {
    	            	synchronized (s){
    	                for(int i = 5;i<11;i++){
    	                        System.out.println("Thread-"+i);
    	                    }
    	                }
    	            }
    	        }).start();

两个线程循环打印12121212….


static SingletonDemo1 s = new SingletonDemo1();
    	/*public static SingletonDemo1 in=new SingletonDemo1();;
    	private SingletonDemo1(){}
    	public static SingletonDemo1 getSingletonDemo1(){
    		return in;
    	}*/
    	public static void main(String[] args) {
    		
    		 new Thread(new Runnable() {
    	            @Override
    	            
    	            public void run() {
    	            	  synchronized (s){
    	                for(int i = 0;i<5;i++){
    	                  
    	                        System.out.println("1");
    	                        s.notify(); //唤醒线程2
    	                        try {
    	                            s.wait();//线程1进入等待
    	                        } catch (InterruptedException e) {
    	                            e.printStackTrace();
    	                        }
    	                    }
    	                }
    	            }
    	        }).start();
    	        //线程2
    	        new Thread(new Runnable() {
    	            @Override
    	            public void run() {
    	            	synchronized (s){
    	                for(int i = 0;i<5;i++){
    	                    
    	                        System.out.println("2");
    	                        s.notify();//唤醒线程1
    	                        try {
    	                            s.wait();//线程2进入等待
    	                        } catch (InterruptedException e) {
    	                            e.printStackTrace();
    	                        }
    	                    }
    	                }
    	            }
    	        }).start();

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转载自blog.csdn.net/qq_40531768/article/details/89336346