两个线程笔试题

题目一

自定义同步容器，容器容量上限为10。可以在多线程中应用，并保证数据线程安全。

方式一：synchronized/wait/notifyAll

public class Test_04<E> {
   
    
    
    private LinkedList<E> list = new LinkedList<E>();
    private final int MAX_SIZE = 10;
    private int count = 0;

    public synchronized void put(E e) {
   
    
    
        while (list.size() == MAX_SIZE) {
   
    
    
            try {
   
    
    
                this.wait();
            } catch (InterruptedException ex) {
   
    
    
                ex.printStackTrace();
            }
        }
        list.add(e);
        count++;
        this.notifyAll();
    }

    public synchronized E get() {
   
    
    
        E e = null;
        while (list.size() == 0) {
   
    
    
            try {
   
    
    
                this.wait();
            } catch (InterruptedException ex) {
   
    
    
                ex.printStackTrace();
            }
        }
        e = list.removeFirst();
        count--;
        this.notifyAll();
        return e;
    }

    public static void main(String[] args) {
   
    
    
        Test_04<Object> m = new Test_04<Object>();
        for (int i = 0; i < 2; i++) {
   
    
    
            new Thread(() -> {
   
    
    
                //容器上限10，25会超出容量限制，会等待
                Object object = null;
                for (int j = 0; j < 25; j++) {
   
    
    
                    object = new Object();
                    m.put