二分查找变形练习

一:x的平方根

在C++库中有sqrt函数可以使用,自己实现


    int mySqrt(int x) {
        if (x <= 1) return x;
        int left = 0, right = x;
        while (left < right) 
        {
            int mid = left + (right - left) / 2;
            if (x / mid >= mid) 
                left = mid + 1;
            else 
                right = mid;
        }
        return right - 1;
    }

二:

int search(vector<int>& nums, int target) 
    {
        int pos=-1;
        int left=0;
        int right=nums.size()-1;
        while(left<=right)
        {
            int mid=left+(right-left)/2;
            if(nums[mid]==target)
            {
                pos=mid;
                break;
            }
            else if(nums[mid]>=nums[left])
            {
                if(nums[mid]>target&&nums[left]<=target)
                {
                    right=mid-1;
                }
                else left=mid+1;
            }
            else
            {
                if(nums[mid]<target&&nums[right]>=target)
                {
                    left=mid+1;
                }
                else right=mid-1;
            }
        }
         return pos;
    }

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转载自blog.csdn.net/Monster7559/article/details/89451254