create table #sql ( Logdatae varchar(50), processinfo varchar(50), [text] varchar(max) ) go INSERT INTO #sql Exec xp_readerrorlog 0 Go SELECT distinct right(text,16)FROM #sql WHERE Logdatae like 'Apr 17 2019%' AND text LIKE 'Login failed for user ''sa''. Reason: Password did not match that for the login provided%'
SQL SERVER-查询爆破sa密码的主机
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转载自www.cnblogs.com/JinweiChang/p/10721513.html
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