python基础之公共方法(十二)

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运算符

运算符 Python 表达式 结果 描述 支持的数据类型
+ [1, 2] + [3, 4] [1, 2, 3, 4] 合并 字符串、列表、元组
* ‘Hi!’ * 4 [‘Hi!’, ‘Hi!’, ‘Hi!’, ‘Hi!’] 复制 字符串、列表、元组
in 3 in (1, 2, 3) True 元素是否存在 字符串、列表、元组、字典
not in 4 not in (1, 2, 3) True 元素是否不存在 字符串、列表、元组、字典
  • +
>>> "hello " + "itcast"
'hello itcast'
>>> [1, 2] + [3, 4]
[1, 2, 3, 4]
>>> ('a', 'b') + ('c', 'd')
('a', 'b', 'c', 'd')
  • *
>>> 'ab'*4
'ababab'
>>> [1, 2]*4
[1, 2, 1, 2, 1, 2, 1, 2]
>>> ('a', 'b')*4
('a', 'b', 'a', 'b', 'a', 'b', 'a', 'b')
  • in
>>> 'itc' in 'hello itcast'
True
>>> 3 in [1, 2]
False
>>> 4 in (1, 2, 3, 4)
True
>>> "name" in {"name":"Delron", "age":24}
True

注意,in在对字典操作时,判断的是字典的键

python内置函数
Python包含了以下内置函数

序号 方法 描述
1 cmp(item1, item2) 比较两个值
2 len(item) 计算容器中元素个数
3 max(item) 返回容器中元素最大值
4 min(item) 返回容器中元素最小值
5 del(item) 删除变量
  • cmp
>>> cmp("hello", "itcast")
-1
>>> cmp("itcast", "hello")
1
>>> cmp("itcast", "itcast")
0
>>> cmp([1, 2], [3, 4])
-1
>>> cmp([1, 2], [1, 1])
1
>>> cmp([1, 2], [1, 2, 3])
-1
>>> cmp({"a":1}, {"b":1})
-1
>>> cmp({"a":2}, {"a":1})
1
>>> cmp({"a":2}, {"a":2, "b":1})
-1

注意:cmp在比较字典数据时,先比较键,再比较值。

  • len
>>> len("hello itcast")
12
>>> len([1, 2, 3, 4])
4
>>> len((3,4))
2
>>> len({"a":1, "b":2})
2

注意:len在操作字典数据时,返回的是键值对个数。

  • max
>>> max("hello itcast")
't'
>>> max([1,4,522,3,4])
522
>>> max({"a":1, "b":2})
'b'
>>> max({"a":10, "b":2})
'b'
>>> max({"c":10, "b":2})
'c'
  • del
    del有两种用法,一种是del加空格,另一种是del()
>>> a = 1
>>> a
1
>>> del a
>>> a

Traceback (most recent call last):
File “”, line 1, in
NameError: name ‘a’ is not defined

>>> a = ['a', 'b']
>>> del a[0]
>>> a
['b']
>>> del(a)
>>> a

Traceback (most recent call last):
File “”, line 1, in
NameError: name ‘a’ is not defined

多维列表/元祖访问的示例

>>> tuple1 = [(2,3),(4,5)]
>>> tuple1[0]
(2, 3)
>>> tuple1[0][0]
2
>>> tuple1[0][2]

Traceback (most recent call last):
File “”, line 1, in
IndexError: tuple index out of range

>>> tuple1[0][1]
3
>>> tuple1[2][2]

Traceback (most recent call last):
File “”, line 1, in
IndexError: list index out of range

>>> tuple2 = tuple1+[(3)]
>>> tuple2
[(2, 3), (4, 5), 3]
>>> tuple2[2]
3
>>> tuple2[2][0]

Traceback (most recent call last):
File “”, line 1, in
TypeError: ‘int’ object is not subscriptable

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