Unity的gameObject判空注意事项

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假设我有一个延迟调用的接口

// 延迟2秒
DelayCallMgr.Call(()=>
{
	// TODO
	
},2);

现在我有一个MyTest 脚本

using UnityEngine;

public class MyTest : MonoBehaviour
{
	void Awake()
	{
		Destroy(gameObject);
		// 延迟2秒调用
		DelayCallMgr.Call(()=>
		{
			if(null != gameObject)
				Debug.Log("null != gameObject");
			else
				Debug.Log("null == gameObject");
		},2);
	}
}

把脚本挂到一个空物体上，运行
会报错：
MissingReferenceException: The object of type ‘MyTest’ has been destroyed but you are still trying to access it.
因为gameObject其实是一个get方法，如果对象不存在，去调用get方法肯定就报错了，所以必须把gameObject缓存起来判断才行：

using UnityEngine;

public class MyTest : MonoBehaviour
{
	GameObject m_selfGo;
	void Awake()
	{
		m_selfGo = gameObject;
		Destroy(m_selfGo);
		// 延迟2秒调用
		DelayCallMgr.Call(()=>
		{
			if(null != m_selfGo)
				Debug.Log("null != gameObject");
			else
				Debug.Log("null == gameObject");
		},2);
	}
}